<span>The formulas are,
Impulse = mv-mu ....... (1)
v^2 = u^2 + 2as .......... (2)
We know that,
u=0
a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2
s=19.6
sub (2) we get,
v^2 = 0+ 2*9.81*19.6
v^2 = 2*9.81*19.6
v^2 = 384.552
v = 19.6099
v = 19.61 m/s
Sub v=19.61 m/s in (1) we get,
Impulse = mv - mu
we know that u=0; v= 19.61 m/s; m= 3.00 kg
Impulse = 3(19.61) - 3(0)
Impulse = 58.83-0
Impulse = 58.83 Ns.
Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>
Answer:
Explanation:
mass of first marble 
Initial velocity of the first marble 
considering right side as positive
Mass of second marble
After collision first marble moves to the left with a velocity of 18 cm/s
i.e. 
considering 
be the velocity of second marble after collision
The Coefficient of restitution is 1 for an elastic collision
Putting values
So, the velocity of the second marble is 22.5 m/s to the right after the collision
(b)Initial kinetic energy =
Final kinetic energy=
Answer:
current is 13.88 A
Explanation:
given data
no of loops = 50 loops
resistance = 40 Ω
R = 15.0 Ω
I = 5.0 amp
N = 18
to find out
rms current
solution
we will apply here transformed principle that is
v(s) / v(p) = I(p) / I(s) = N(s) / N(p) ....................1
here p is primary and s is secondary
put here all these value
5 / I(s) = 18 / 50
I(s) = 250 /18
I(s) = 13.88
so current is 13.88 A
