Answer:
Force from the support closest = 79.8 N
Force from the support furthest = 61.9 N
Explanation:
Let's say the length of the beam is L. Let's say A is the near end of the beam and B is the far end of the beam.
Draw a free body diagram. There are four forces on the beam:
Reaction force Ra at the near end (0),
Reaction force Rb at the far end (L),
Weight force of the beam Mg at the center (L/2),
Weight force of the book mg at L/4 from A.
Sum of torques at A:
∑τ = Iα
Rb (L) − Mg (L/2) − mg (L/4) = 0
Rb (L) = Mg (L/2) + mg (L/4)
Rb = ½ Mg + ¼ mg
Rb = (½ M + ¼ m) g
Rb = (½ (10.8 kg) + ¼ (3.66 kg)) (9.8 m/s²)
Rb = 61.9 N
Sum of forces in the y direction:
∑F = ma
Ra + Rb − Mg − mg = 0
Ra = Mg + mg − Rb
Ra = (M + m) g − Rb
Ra = (10.8 kg + 3.66 kg) (9.8 m/s²) − 61.9 N
Ra = 79.8 N
Answer:
2.64 m/s
Explanation:
Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna
Momentum = MV
Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s
Momentum of the tun final before collision = 100 × 0.5 = 50 kgm/s
Total momentum before collision = 1800 + 50 = 1850 kgm/s
Let's assume that they move together after collision. Then,
1850 = ( 600 + 100 ) V
1850 = 700V
V = 1850 / 700
V = 2.64285 m/s
Therefore, the momentum of the shark after collision is 2.64 m/ s approximately
The human eye is not capable of seeing radiation wavelengths outside the visible Spectrum, i hope this answers your question :)
Refractor, It's a refractor-esque telescope
The formula is:
v = v o + a t
6 = 10 + 3 * a
3 a = 10 - 6
a = 4 : 3
a = - 1.33 m/s² ( because the car slows down )
Answer: The average acceleration of the car is - 1.33 m/s²
