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AlladinOne [14]
2 years ago
5

How many significant figures are in 31400

Chemistry
1 answer:
mr_godi [17]2 years ago
5 0

Answer: The Answer Is 3!

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The following reaction was carried out in a 3.25 L reaction vessel at 1100 K:
kipiarov [429]

Answer : The value of reaction quotient Q is, 0.498

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][H_2]}{[H_2O]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now we have to calculate the concentration of H_2O,CO\text{ and }H_2

\text{Concentration of }H_2O=\frac{\text{Moles of }H_2O}{\text{Volume of solution}}=\frac{13.3mol}{3.25L}=4.09M

and,

\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{3.40mol}{3.25L}=1.05M

and,

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{6.30mol}{3.25L}=1.94M

Now put all the given values in the above expression, we get:

Q=\frac{(1.05)\times (1.94)}{(4.09)}=0.498

Thus, the value of reaction quotient Q is, 0.498

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3 years ago
Where does biomass comes from
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DOES a single population have a lot of genetic diversity in it when it is always reproducing together?
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I know how to solve it with D=M/V and M1V1 however the answer isn’t correct. Help me please
lara31 [8.8K]

Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

Mass of hexane =?

Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

= 86.172 g/mol

Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

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From the stomach, the food travels to the small intestine. This happens with the help of a movement known as peristalsis. Juices are released in the small intestine, which helps in the breakdown of carbohydrates, starch, and proteins. 
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