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motikmotik
3 years ago
13

2 pts

Chemistry
1 answer:
IrinaK [193]3 years ago
4 0
Natural resource i think
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Rewrite these word equations as chemical equations.
stich3 [128]

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What is the freezing point in °C) of a 0.195 m
Elina [12.6K]

Answer:

T_S=-1.09\°C

Explanation:

Hello!

In this case, since the freezing point depression for a solution is computed via:

(T_S-T_W)=-imK_f

Whereas TW is the freezing temperature of water, TS that of the solution, i the van't Hoff's factor (3 for K2S as it ionizes properly), m the molality of the solution and Kf the freezing point constant of water. Thus, we plug in to obtain:

(T_S-0\°C)=-3*0.195m*1.86\frac{\°C}{m}\\\\T_S=-1.09\°C

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3 years ago
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False

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