<h3>
<em>Answer:770</em></h3><h3 /><h3>
<em>R=I×100/P×T</em></h3>
<em>R</em><em>=</em><em> </em><em>1</em><em>1</em><em>5</em><em>5</em><em>×</em><em>1</em><em>0</em><em>0</em><em>/</em><em>6</em><em>0</em><em>0</em><em>0</em><em>×</em><em>3</em><em>/</em><em>1</em><em>2</em>
<em>R</em><em>=</em><em> </em><em>1</em><em>1</em><em>5</em><em>5</em><em>×</em><em>2</em><em>/</em><em>3</em>
<h3>
<em>R=770</em></h3>
Answer:
58.44 g/mol
Explanation:
just got done with this unit two weeks ago
Answer:
d. 99.63% and 0.364%, respectively
Explanation:
The average mass of a nitrogen atom is 14.006 amu
14N-14.00307 amu with 0.9963 fractional abundance
1SN- 15.000108 amu with 0.00364 fractional abundance.
The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.
In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.
14N-14.00307 = 0.9963* 100% = 99.63%
1SN- 15.000108 = 0.00364 * 100% = 0.364%
Explanation:
There are two aspects of a reaction:
Thermodynamics:
Combustion of the compound is reaction with oxygen.
The carbohydrates contain more content of oxygen as compared to fats.
Hence, carbohydrates have lot of oxygen content which are already partially oxidized as compared to fats. Hence, combustion of the carbohydrates is a faster process.
Kinetics:
The molecular reacts also shows that the combustion of the carbohydrates is a faster process.
