Try c I think is the most accurate one
Answer:
- The speed of the wave in the rope is 2 m/s
Explanation:
1. <u>Data</u>:
a) ν = 4 Hz
b) λ = 0.5 m
c) s = ?
2. <u>Physical principles and formula</u>:
The propagation of waves in a rope is a classical example of <em>transverse waves</em>: the pulse is inflected in the <em>vertical</em> direction and the wave travels in the <em>horizontal</em> direction, i.e. the pulse or vibration is perpendicular to the motion of the media particles.
The equation that relates <em>speed (s), wavelength (λ), frequency (ν) </em>is:
- wavelength = speed × period
- wavelenfth = speed / frequency
- meter = (meter/second) / second⁻¹
3. <u>Solution</u>:
Answer:
401135 kJ
Explanation:
From the balanced quation,
(q/n) = CΔE
Molar heat of combustion = 7.85kJk × (303.81-298.70)k
= 7.85kj × 5.11
= 40.1135kj
0.0340 g O2
<em>Step 1.</em> Write the balanced chemical equation
4Fe(OH)^(+) + 4OH^(-) + O2 + 2H2O → 4Fe(OH)3
<em>Step 2</em>. Calculate the moles of Fe^(2+)
Moles of Fe^(2+) = 50.0 mL Fe^(2+) × [0.0850 mmol Fe^(2+)/1 mL Fe^(2+)]
= 4.250 mmol Fe^(2+)
<em>Step 3</em>. Calculate the moles of O2
Moles of O2 = 4.250 mmol Fe^(2+) × [1 mmol O2/4 mmol Fe^(2+)]
= 1.062 mmol O2
<em>Step 4</em>. Calculate the mass of O2
Mass of O2 = 1.062 mmol O2 × (32.00 mg O2/1 mmol O2) = 34.0 mg O2
= 0.0340 g O2
<span>D. It shows that the electrons within an atom do not have sharp boundaries.</span>
