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Aleksandr-060686 [28]
3 years ago
10

A flask has a mass of 78.23g when empty and 593.63g when filled with water.When the same flask is filled with concentrateds ulfu

ric acid, H2SO4, its mass is 1026.57g. What is the density of concentrated sulfuric acid?(Assume water has a density of 1.00g/cm3 at the temperature of the measurement.)
Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer:

Density of concentrated H2SO4 = 1.99g/cm^3 = 1991.79Kg/m^3

Explanation:

mass of empty flask = 78.23g mass of flask filled when with water = 593.63g.

mass of flask filled when with concentrateds sulfuric acid, H2SO4 = 1026.57g

Mass of water = (mass of flask filled when with water) -

(mass of empty flask) = 593.63g - 78.23g = 515.4g

Volume of flask = volume of water = volume of concentrateds sulfuric acid, H2SO4 =

(mass of water)/ density of water) = 515.4g/1.00g/cm^3 = 515.4cm^3

The density of concentrated sulfuric acid is given by

Density of concentrated H2SO4 = (mass of H2SO4) ÷ (volume of H2SO4) = 1026.57g/515.4cm^3 = 1.99g/cm^3 = 1991.79Kg/m^3

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I believe the answer is A
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Joan needs a 0.053-M solution of HCl, but only has access to 2.12-M HCl, a 10-mL graduated pipet, and a 25-mL volumetric flask.
dmitriy555 [2]

Answer:

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

Explanation:

Molarity of HCl Joan has access to = M_1=2.12 M

Volume of 2.12 M of HCl Joan use = V_1=?

Molarity of HCl Joan desired = M_2=0.053 M

Volume of 0.053 M of HCl Joan can prepare = V_2=25 mL

M_1V_1=M_2V_2

V_1=\frac{M_2V_2}{M_1}

=\frac{0.053 M\times 25 mL}{2.12 M}=0.625 mL

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

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3 years ago
At PO2 = 40 mm Hg, which statement about the saturation of either myoglobin (Mb) or hemoglobin (Hb) is true? At PO2 = 40 mm Hg,
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At this partial pressure of oxygen, Mb would be almost completely saturated but Hb would not.  

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3 years ago
PLSS HELP ASAP it's due
BartSMP [9]
<h3>Answer:</h3>

87.02%

<h3>Explanation:</h3>

Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.

In this case we are given;

Mass of Zinc as 7.23 g

Actual volume of Hydrogen gas produced as 2.16 L

We are required to calculate the percentage yield of Hydrogen gas;

<h3>Step 1: Write a balanced equation for the reaction</h3>

The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>

Moles are given by dividing mass with molar mass

Moles = Mass ÷ Molar mass

Molar mass of Zinc = 65.38 g/mol

Therefore;

Number of moles = 7.23 g ÷ 65.38 g/mol

                             = 0.1106 moles

<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>

From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.

Therefore, Moles of hydrogen gas = Moles of Zinc × 1

                                                         = 0.1106 moles × 1

                                                         = 0.1106 moles

<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>

At STP, 1 mole of a gas occupies 22.4 Liters

Therefore;

Volume of Hydrogen = Number of moles × 22.4 L

                                   = 0.1106 mole × 22.4 L

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<h3>Step 5: Calculate the percent yield </h3>

Percent yield = (Actual yield ÷ Theoretical Yield) × 100%

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                     = 87.20%

Thus, the percent yield of hydrogen gas produced is 87.02%

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