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Aleksandr-060686 [28]
3 years ago
10

A flask has a mass of 78.23g when empty and 593.63g when filled with water.When the same flask is filled with concentrateds ulfu

ric acid, H2SO4, its mass is 1026.57g. What is the density of concentrated sulfuric acid?(Assume water has a density of 1.00g/cm3 at the temperature of the measurement.)
Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer:

Density of concentrated H2SO4 = 1.99g/cm^3 = 1991.79Kg/m^3

Explanation:

mass of empty flask = 78.23g mass of flask filled when with water = 593.63g.

mass of flask filled when with concentrateds sulfuric acid, H2SO4 = 1026.57g

Mass of water = (mass of flask filled when with water) -

(mass of empty flask) = 593.63g - 78.23g = 515.4g

Volume of flask = volume of water = volume of concentrateds sulfuric acid, H2SO4 =

(mass of water)/ density of water) = 515.4g/1.00g/cm^3 = 515.4cm^3

The density of concentrated sulfuric acid is given by

Density of concentrated H2SO4 = (mass of H2SO4) ÷ (volume of H2SO4) = 1026.57g/515.4cm^3 = 1.99g/cm^3 = 1991.79Kg/m^3

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Answer:

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Explanation:

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Mass of NH₃ = 6.75 g

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Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 6.75 / 17

Mole of NH₃ = 0.397 mole

Next, we shall determine the number of mole of NO produced by the reaction of 0.397 mole of NH₃. This can be obtained as follow:

4NH₃ + 5O₂ —> 4NO + 6H₂O

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Therefore, 0.397 mole of NH₃ will also react to produce 0.397 mole of NO.

Finally, we shall determine the mass of 0.397 mole of NO. This can be obtained as follow:

Mole of NO = 0.397 mole

Molar mass of NO = 14 + 16 = 30 g/mol

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Which of the following reactions have a positive ΔSrxn? Check all that apply.
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Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

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Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

  • <em><u>2A(g) + B(g) → C(g)</u></em>

Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

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Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

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With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

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Answer:

The solution is always homogeneous mixture and transparent through which the light can travel. The mixture of water and sugar is a solution because sugar is soluble in water and form homogeneous mixture while the sand can not dissolve in water and sand particles scatter the light.

Explanation:

Solution:

"The solution is always homogeneous mixture and transparent through which the light can travel"

The mixture of water and sugar is a solution because sugar is soluble in water and form homogeneous mixture. The solubility of sugar is high as compared to the sand in water because the negative and positive ends of sucrose easily dissolve into the polar solvent i.e, water

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