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qwelly [4]
3 years ago
9

Riley is cleaning his room(a once a year activity) and pulls the Hoover with a force of 8 N a total distance of 20 metres. How m

uch work does he do? Where does this energy end up​
Physics
1 answer:
Radda [10]3 years ago
7 0

Answer:

160J

Explanation:

Given force = 8N and total distance = 20 meters

Workdone = force x distance

= 8 x 20

= 160J

Therefore, workdone by Riley in pulling the hoover is 160J

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Describe the importance of conservative forces to conservation of energy.
qwelly [4]
Not sure but just coming to say good luck and take your time
6 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
Read 2 more answers
A 2.0-mm-diameter copper ball is charged to 40 nC . What fraction of its electrons have been removed? The density of copper is 8
murzikaleks [220]

Answer:

0.02442 × 10⁻⁹

Explanation:

Given:

Diameter of copper ball = 2.00 mm = 0.002 m

Charge on ball = 40 nC = 40 × 10⁻⁹ C

Density of copper = 8900 Kg/m³

Now,

The number of electrons removed, n = \frac{\textup{Charge on ball}}{\textup{Charge of an electron}}

also, charge on electron = 1.6 × 10⁻¹⁹ C

Thus,

n = \frac{40\times10^{-9}}{1.6\times10^{-19}}

or

n = 25 × 10¹⁰ Electrons

Now,

Mass of copper ball = volume × density

Or

Mass of copper ball =  \frac{4}{3}\pi(\frac{d}{2})^3  × 8900

or

Mass of copper ball =  \frac{4}{3}\pi(\frac{0.002}{2})^3  × 8900

or

Mass of copper ball = 0.03726 grams

Also,

molar mass of copper = 63.546 g/mol

Therefore,

Number of mol of copper in  0.03726 grams = \frac{ 0.03726}{63.546}

or

Number of mol of copper in  0.03726 grams = 5.86 × 10⁻⁴ mol

and,

1 mol of a substance contains = 6.022 × 10²³ atoms

Therefore,

5.86 × 10⁻⁴ mol of copper contains = 5.86 × 10⁻⁴ × 6.022 × 10²³ atoms.

or

5.86 × 10⁻⁴ mol of copper contains = 35.88 × 10¹⁹ atoms

Now,

A neutral copper atom has 29 electrons.  

Therefore,

Number of electrons in ball = 29 × 35.88 × 10¹⁹ = 1023.37 × 10¹⁹ electrons.

Hence,

The fraction of electrons removed = \frac{25\times10^{10}}{1023.37\times10^{19}}

or

The fraction of electrons removed = 0.02442 × 10⁻⁹

3 0
4 years ago
Recognizing the face of someone you run into at the mall is a function of the __________ hemisphere; being able to retrieve that
Alchen [17]

Answer:

right; left

Explanation:

The right hemisphere of the brain has a schema formation capacity, this can be applied to recognize faces. The left hemisphere is in charge of the memory and therefore to recall names.

I hope you find this information useful and interesting! Good luck!

5 0
4 years ago
An object is placed at a certain distance on the principal axis of a concave mirror. The image is formed at a distance of 30cm f
Nikolay [14]

the object distance is 10cm

6 0
3 years ago
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