Answer:B
Explanation:
Because chemical energy fuels your body with energy so without it u wont have enough energy to move.
 
        
             
        
        
        
Answer:
C) 50 m/s
Explanation:
With the given information we can calculate the acceleration using the force and mass of the box. 
Newton's 2nd Law: F = ma
- 5 N = 1 kg * a 
- a = 5 m/s² 
List out known variables:
- v₀ = 0 m/s
- a = 5 m/s² 
- v = ?
- Δx = 250 m 
Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:
Substitute known values into the equation and solve for v.
- v² = (0)² + 2(5)(250) 
- v² = 2500 
- v = 50 m/s
The final velocity of the box is C) 50 m/s. 
 
        
             
        
        
        
Answer:
18.9 m. 
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s 
Final velocity (v) = 70 km/h
Height (h) =?
Next, we shall convert 70 km/h to m/s. This can be obtained as follow:
3.6 km/h = 1 m/s
Therefore, 
70 km/h = 70 km/h × 1 m/s / 3.6 km/h
70 km/h = 19.44 m/s
Finally, we shall determine the height. This can be obtained as follow:
Initial velocity (u) = 0 m/s 
Final velocity (v) = 19.44 m/s
Acceleration due to gravity (g) = 10 m/s²
Height (h) =?
v² = u² + 2gh
19.44² = 0² + (2 × 10 × h)
377.9136 = 0 + 20h
377.9136 = 20h
Divide both side by 20
h = 377.9136 / 20
h = 18.9 m
Thus, the car will fall from a height of 18.9 m
 
        
             
        
        
        
Answer:
  Coil 2 have  235  loops
Explanation:
Given  
The number of loops in coil 1 is n
₁=
159
The emf induced in coil 1 is  ε
₁
=
2.78
V
The emf induced in coil 2 is  ε
₂
=
4.11
V
Let
n
₂  is the number of loops in coil 2.
Given, the emf in a single loop in two coils are same. That is,
ϕ
₁/n
₁=
ϕ
₂
n
₂⟹
2.78/159
=
4.11/
n
₂
n₂=
n₂=235
Therefore, the coil 2 has  n
₂=
235  loops.
 
        
                    
             
        
        
        
Answer:
a force that is able to act at a distance
Explanation:
:)