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lys-0071 [83]
3 years ago
5

If a person is throwing darts at a target in shoots three in a row in the same spot on the 20 section outer ring, but none in th

e bull’s-eye, the person throwing could be described as _____.
1) accurate, but not exact
2) precise, not accurate
3) accurate, but not precise
4) exact, but not precise
Physics
2 answers:
Harman [31]3 years ago
8 0
2)precise,not accurate
Oksi-84 [34.3K]3 years ago
5 0
The answer would be 2) precise, not accurate
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An elevator manufacturing company is stress-testing a new elevator in an airless test shaft. The elevator is traveling at an unk
devlian [24]

Answer:

3.192 m/s

Explanation:

t = Time taken = 0.900 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 1.1 meters

a = Acceleration due to gravity = 9.81 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1.1-\frac{1}{2}\times 9.81\times 0.9^2}{0.9}\\\Rightarrow u=-3.192\ m/s

Velocity of the elevator when it snapped is 3.192 m/s

4 0
3 years ago
There is friction between the block and the
Norma-Jean [14]

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

4 0
3 years ago
An eagle flew for 3 hours at 115 km/h and 5 hours at 136 km/h. How far did the eagle fly?
Yanka [14]

Answer:

the eagle flew 1,025 km

Explanation:

since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.

3 0
3 years ago
PLEASE HELP AND HURRY
Ahat [919]

Answer:

B

Explanation:

6 0
3 years ago
Read 2 more answers
A 2.00 kg object is moving in a circular path with a radius of 5.00 cm. The object starts from rest and with constant angular ac
Rom4ik [11]

Answer:

0.800 m/s²

Explanation:

First, calculate the angular acceleration:

ω = αt + ω₀

6.00 rad/s = α (3.00 s) + 0 rad/s

α = 2.00 rad/s²

Now calculate the angular velocity at t = 2.00 s:

ω = αt + ω₀

ω = (2.00 rad/s²) (2.00 s) + 0 rad/s

ω = 4.00 rad/s

Calculate the linear velocity:

v = ωr

v = (4.00 rad/s) (0.0500 m)

v = 0.200 m/s

Finally, calculate the centripetal acceleration:

a = v² / r

a = (0.200 m/s)² / (0.0500 m)

a = 0.800 m/s²

3 0
3 years ago
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