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lys-0071 [83]
4 years ago
5

If a person is throwing darts at a target in shoots three in a row in the same spot on the 20 section outer ring, but none in th

e bull’s-eye, the person throwing could be described as _____.
1) accurate, but not exact
2) precise, not accurate
3) accurate, but not precise
4) exact, but not precise
Physics
2 answers:
Harman [31]4 years ago
8 0
2)precise,not accurate
Oksi-84 [34.3K]4 years ago
5 0
The answer would be 2) precise, not accurate
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Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the
julsineya [31]

Explanation:

The expression is :

A=B^nC^m

A =[LT], B=[L²T⁻¹], C=[LT²]

Using dimensional of A, B and C in above formula. So,

A=B^nC^m\\\\\ [LT]=[L^2T^{-1}]^n[LT^2}]^m\\\\\ [LT]=L^{2n}T^{-n}L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}

Comparing the powers both sides,

2n+m=1 ...(1)

2m-n=1 ...(2)

Now, solving equation (1) and (2) we get :

n=\dfrac{1}{5}\\\\m=\dfrac{3}{5}

Hence, the correct option is (E).

5 0
3 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0
3 years ago
An object moving at a constant speed of 25 m/s is making a turn with a radius of curvature of 7 m (this is the radius of the "ki
prisoha [69]

Answer:

- 278.34 kg m/s^2

Explanation:

The rate of the change of momentum is the same as the force.

The force that an object feels when moviming in a circular motion is given by:

F = -mrω^2

Where ω is the angular speed and r is the radius of the circumference

Aditionally, the tangential velocity of the body is given as:

v = rω

The question tells us that

v = 25 m/s

r = 7m

mv = 78 kg m/s

Therefore:

m = (78 kg m/s) / (25 m/s) = 3.12 kg

ω = (25 m/s) / (7 m) = 3.57 (1/s)

Now, we can calculate the force or rate of change of momentum:

F = - (3.12 kg) (7 m)(3.57 (1/s))^2

F = - 278.34 kg m/s^2

4 0
3 years ago
What is the difference between soldering and solder? <br>​
andrey2020 [161]

Answer:

Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.

Explanation:

<em>Hope this helps :)</em>

<em>Pls mark brainliest :3 </em>

<em>And have an amazing day <3 </em>

4 0
2 years ago
Read 2 more answers
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
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