Answer:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
Explanation:
Na(s) + HCl(aq) —> NaCl(aq) + H2(g)
Writing an ionic equation will actually help us to understand the equation and also to balance it. This is illustrated below:
Na + H+Cl-
Na is higher than H in the activity series and as such, it will displaces H from the solution and form NaCl with H2 liberated as shown below
Na + H+Cl- —> Na+Cl- + H2
Now, put 2 in front of Na, H+Cl- and Na+Cl- to balance the equation as shown below:
2Na + 2H+Cl- —> 2Na+Cl- + H2
Now we can write the elemental equation as follow:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
Answer: give me more of an explaination
Explanation:
Answer:
7.21 grams is the mass of methane
Explanation:
We may use the Ideal Gases Equation to solve this:
P. V = n. R. T
Let's determine the moles of Ar
18 g . 1 mol/ 39.9 g = 0.451 mol
In both situations, volume, temperature and pressure are the same so the moles of methane will also be the same as Argon's.
Let's convert the moles to mass of CH4.
0.451 mol . 16g/1mol = 7.21 grams