Question

The asteroid Ceres has a mass 6.797 × 1020 kg and a radius of 472.9 km. What is g on the surface? The value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .

Answer 1

Answer:

$g=0.20\ m/s^2$    

Explanation:

It is given that,

Mass of the asteroid Ceres, $m=6.797\times 10^{20}\ kg$

Radius of the asteroid, $r=472.9\ km=472.9\times 10^3\ m$

The value of universal gravitational constant, $G=6.67259\times 10^{-11}\ N.m^2/kg^2$

We know that the expression for the acceleration due to gravity is given by :

$g=\dfrac{Gm}{r^2}$

$g=\dfrac{6.67259\times 10^{-11}\times 6.797\times 10^{20}}{(472.9\times 10^3)^2}$

$g=0.20\ m/s^2$

So, the value of acceleration due to gravity on that planet is $0.20\ m/s^2$. Hence, this is the required solution.