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Ad libitum [116K]
3 years ago
13

The asteroid Ceres has a mass 6.797 × 1020 kg and a radius of 472.9 km. What is g on the surface? The value of the universal gra

vitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .
Physics
1 answer:
raketka [301]3 years ago
8 0

Answer:

g=0.20\ m/s^2    

Explanation:

It is given that,

Mass of the asteroid Ceres, m=6.797\times 10^{20}\ kg

Radius of the asteroid, r=472.9\ km=472.9\times 10^3\ m

The value of universal gravitational constant, G=6.67259\times 10^{-11}\ N.m^2/kg^2

We know that the expression for the acceleration due to gravity is given by :

g=\dfrac{Gm}{r^2}

g=\dfrac{6.67259\times 10^{-11}\times 6.797\times 10^{20}}{(472.9\times 10^3)^2}

g=0.20\ m/s^2

So, the value of acceleration due to gravity on that planet is 0.20\ m/s^2. Hence, this is the required solution.

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