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saveliy_v [14]
3 years ago
10

Is it possible to create a visual model (stop motion) of a wave motion using the differential equation for simple harmonic oscil

lation and how so?
Physics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

  • Yes.

Explanation:

A particular solution for the 1D wave equation has the form

\Psi(x,t) \ = \ A \ sin ( \ k x \ + \omega t \ + \phi \ )

where A its the amplitude, k the wavenumber, ω the angular frequency and φ the phase angle.

Now, for any given position x_0, we can use:

\phi_0 \ = \ \phi \ + \ k x_0

so, the equation its:

\Psi(x_0,t) \ = \ A \ sin ( \omega t \ + \ \phi_0 ).

This is the equation for a simple harmonic oscillation!

So, for any given point, we can use a simple harmonic oscillation as visual model. Now, when we move a \delta distance from the original position, we got:

x_1 = x_0 + \delta

and

\phi_1 = \phi  \ + k x_1

now, this its

\phi_1 = \phi  \ + k ( x_0 + \delta)

\phi_1 = \phi  \ + k  x_0 + k \delta

\phi_1 = \phi_0 + k \delta

So, there its a phase angle difference of k \delta. We can model this simply by starting the simple harmonic oscillation with a different phase angle.

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nasty-shy [4]

Answer:

B. Transformer

Explanation:

A transformer is a device that is used to either raise or lower voltages and currents in an electrical circuit. In modern electrical distribution systems, transformers are used to boost voltage levels so as to decrease line losses during transmission. It basically trades voltage for current in a circuit, while not affecting the total electrical power. This means it takes high-voltage electricity with a small current and changes it into low-voltage electricity with a large current, or vice versa.

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A scientist wants to learn about Earth's oceans. Which of the following
ahrayia [7]
Hydrosphere - all the waters on the earth’s surface.
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A 0.683 kg mass moves in SHM at the end of a spring. It takes 1.41 s to move from the position with the spring fully extended to
dsp73

Answer:

Spring constant of the spring will be equal to 9.255 N /m          

Explanation:

We have given mass m = 0.683 kg

Time taken to complete one oscillation is given T = 1.41 sec

We have to find the spring constant of the spring

From spring mass system time period is equal to T=2\pi \sqrt{\frac{m}{K}}, here m is mass and K is spring constant

So 1.41=2\times 3.14\sqrt{\frac{0.683}{K}}

0.2245=\sqrt{\frac{0.683}{K}}

Squaring both side

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