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saveliy_v [14]
4 years ago
10

Is it possible to create a visual model (stop motion) of a wave motion using the differential equation for simple harmonic oscil

lation and how so?
Physics
1 answer:
Alexeev081 [22]4 years ago
8 0

Answer:

  • Yes.

Explanation:

A particular solution for the 1D wave equation has the form

\Psi(x,t) \ = \ A \ sin ( \ k x \ + \omega t \ + \phi \ )

where A its the amplitude, k the wavenumber, ω the angular frequency and φ the phase angle.

Now, for any given position x_0, we can use:

\phi_0 \ = \ \phi \ + \ k x_0

so, the equation its:

\Psi(x_0,t) \ = \ A \ sin ( \omega t \ + \ \phi_0 ).

This is the equation for a simple harmonic oscillation!

So, for any given point, we can use a simple harmonic oscillation as visual model. Now, when we move a \delta distance from the original position, we got:

x_1 = x_0 + \delta

and

\phi_1 = \phi  \ + k x_1

now, this its

\phi_1 = \phi  \ + k ( x_0 + \delta)

\phi_1 = \phi  \ + k  x_0 + k \delta

\phi_1 = \phi_0 + k \delta

So, there its a phase angle difference of k \delta. We can model this simply by starting the simple harmonic oscillation with a different phase angle.

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A 86.3 μC charge has a potential of 17.5 V. Determine how much kinetic energy, in eV, this charge could have.
almond37 [142]

Answer:

9.44 eV

Explanation:

q = Amount of charge = 86.3 μC = 86.3 x 10⁻⁶ C     (Since 1 μC =  10⁻⁶ C)

V = Electric potential of the charge = 17.5 Volts

U = Amount of electric potential energy carried by charge

Amount of electric potential energy carried by charge is given as

U = q V

Inserting the values

U = (86.3 x 10⁻⁶) (17.5)

U = 0.00151 J

U = \frac{0.00151}{1.6\times 10^{-19}}

U = 9.44 eV

KE = Kinetic energy the charge could have

Using conservation of energy

KE = U

KE = 9.44 eV

5 0
3 years ago
What is drag? In what situations might it act on the force of gravity?
stepan [7]
Drag is passive, therefore it does not act on gravity. Drag is a mechanical resistance to motion. If the motion in question was induced by gravity drag it can impede that motion, but has no effect on the gravity. 

hope this helps!
7 0
3 years ago
Read 2 more answers
An amplifier produces a sound wave with a power of 1.00 μW (micro-Watt). If it is a point source and radiates uniformly in all d
gtnhenbr [62]

Answer:

(a) I=8.84*10^{-9}W/m^{2}

(b) \beta =39.46dB

Explanation:

Given data

The source is 1.00 μW

The point is 3m away from the point source

For Part (a)

The intensity at a certain distance from a point source that emits sound wave is given as:

I=\frac{P_{s} }{4\pi r^{2} }\\I=\frac{1*10^{-6}W  }{4\pi (3m)^{2} } \\I=8.84*10^{-9}W/m^{2}

For Part (b)

The Sound level is given by

β=(10dB)×log(I/I₀)

Where

I₀=1×10⁻¹²W/m²

Substitute the given values to find Sound level

So

\beta =(10dB)log(\frac{8.84*10^{-9}W/m^{2}  }{1*10^{-12}W/m^{2}} )\\\beta =39.46dB

4 0
3 years ago
An empty rubber balloon has a mass of 12.5 g. The balloon is filled with helium at a density of 0.181 kg/m3. At this density the
Eduardwww [97]

Answer: 1.14 N

Explanation :

As any body submerged in a fluid, it receives an upward force equal to the weight of the fluid removed by the body, which can be expressed as follows:

Fb = δair . Vb . g = 1.29 kg/m3 . 4/3 π (0.294)3  m3. 9.8 m/s2

Fb = 1.34 N

In the downward direction, we have 2 external forces acting upon the balloon: gravity and the tension in the line, which sum must be equal to the buoyant force, as the balloon is at rest.

We can get the gravity force as follows:

Fg = (mb +mhe) g  

The mass of helium can be calculated as the product of the density of the helium times the volume of the balloon (assumed to be a perfect sphere), as follows:

MHe = δHe . 4/3 π (0.294)3 m3 = 0.019 kg

Fg = (0.012 kg + 0.019 kg) . 9.8 m/s2 = 0.2 N

Equating both sides of Newton´s 2nd Law in the vertical direction:

T + Fg = Fb

T = Fb – Fg = 1.34 N – 0.2 N = 1.14 N

6 0
3 years ago
According to Galileo's pendulum theory, which factor determines the time taken to swing through one complete cycle?
Lesechka [4]
It depends on the length of the string and the speed its swinging at. If its short then it will reach the full swing in less of a time but if its a longer string then it would take a longer time to make a full swing.
6 0
3 years ago
Read 2 more answers
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