You can use the formula P1V1= P2V2
(1.90)(6.32L)=P1(3.49 L).
Solve for the unknown.
P1= 3.44 atm
0.164 g/L is the density of a sample of 1.00 mole of 
at 793mmhg and -9.00 degrees celcius.
<h3>What is density?</h3>
Density is the mass of a unit volume of a material substance. The formula for density is d = 
, where d is density, M is mass, and V is volume.
Given data:
n = 1.00 mole
P=793 mm hg =1.04342 atm
T=-9.00 degree celcius = -9.00 + 273= 264 K
V=?
Using Ideal Gas Law equation:
PV = n R T
R = gas constant = 0.082057 L-atm/(mol-K)
(1.04342 atm)(V) = 5 X 0.082057 L-atm/(mol-K) X 264 K
V = 103.67 Liters
Now calculate density:
Mole weight of = 1.00 mole
So, the mass of = 17.031 g
Density = 
Density = 
= 0.164 g/L
Hence, 0.164 g/L is the density of a sample of 1.00 mole of at 793mmhg and -9.00 degrees celcius.
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Answer:
J.J. Thomson’s experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged “soup.”
Answer:
The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.
Explanation:
Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;
P ∝ V
P V = K
P1 V1 = P2 V2
Parameters :
P1 = Initial pressure of the gas = 750 mmHg
V1 = Initial pressure of the gas = 2. 00 Liters
P2 = Final pressure of the gas = 600 mmHg
V2 = Fimal volume of the gas = ? Liters
Calculations :
V2 = P1 V1 ÷ P2
V2= 750 × 2. 00 ÷ 600
V2 = 1500 ÷ 600
V2 = 2.5 Liters.
Therefore, the new volume of the gas is 2. 5 Liters.
With every electron stationed in its own orbital or paired off with each other in the higher energy level, the energy level is balanced and stable. The atoms that utilize this exception are Molybdenum, Chromium, Gold, Silver, and Copper.
