There are 5 significant figures in <span>147,320.</span>
Answer:
adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.
Explanation:
Barium sulfate is an insoluble ionic compound since it is insoluble in water.
We can differentiate barium ions and sulfate ions away from the surface if we add a small amount of solid barium sulfate is mixed with water and shaken.
The action would shift this reaction away from solid barium sulfate and toward the dissolved ions are adding silver ions , adding chloride ions, removing chloride ions and removing silver chloride.
An ionic and covalent quality has in every molecular bond.
In barium sulfate barium has lowest electronegativities.
Oxygen has highest electronegativities.
so the bond between both barium and sulfate is ionic in character.
Answer:
Pure solids or liquids are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction. The concentration of a pure liquid or solid equals its density divided by its molar mass.
Explanation:
Hope this helps!!!
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
And the total number of snow flakes per minute on the entire lawn is:
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
In one hour (or 60 minutes) we get a total of:
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
The total mass of which would be:
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
So 54.432 kg of snow accumulates every hour on the lawn.</span>
Answer:51.1%
Explanation:
Mass percent : It is defined as the mass of the given component present in the total mass of the compound. Formula used : First we have to calculate the mass of and . Mass of = 18 g/mole Mass of = 7 × 18 g/mole = 126 g/mole Mass of = 246.47 g/mole Now put all the given values in the above formula, we get the mass percent of in . Therefore, the mass percent of in is, 51.1%