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alina1380 [7]
4 years ago
10

Please explain how roasting a hot dog over a fire involves all three forms of heat transfer. Please use full sentences and corre

ct grammar!
Chemistry
1 answer:
sergejj [24]4 years ago
3 0

Ok so First of all we start with the fire. The fire gives off radiation because you can feel the heat through space. The fire also gives of conduction because you put the hotdog on the fire to cook it, and the hotdog will give off steam when it is hot causing it to give of Convection.

There is how cooking a hotdog over a fire uses all three heat transfer

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At 500°C the equilibrium constant, Kp, is 4.00 × 10–4 for the equilibrium: 2HCN(g) H2(g) + C2N2(g) What is Kp for the following
Andrews [41]

<u>Answer:</u> The value of K_p for the equation is 2.5\times 10^3

<u>Explanation:</u>

The given chemical reaction is:

2HCN(g)\rightleftharpoons H_2(g)+C_2N_2(g);K_1

The chemical equation for which the equilibrium constant is to be calculated follows:

H_2(g)+C_2N_2(g)\rightleftharpoons 2HCN(g);K_p

As, the equation is the result of the reverse of given reaction. So, the equilibrium constant for the equation will be the inverse of equilibrium constant for the given reaction.

The value of equilibrium constant for the equation is:

K_p=\frac{1}{K_1}

We are given:

K_1=4.00\times 10^{-4}

Putting values in above equation, we get:

K_p=\frac{1}{4.00\times 10^{-4}}=2.5\times 10^3

Hence, the value of K_p for the equation is 2.5\times 10^3

3 0
4 years ago
A mixture containing nitrogen and hydrogen weighs 3.48 g and occupies a volume of 7.47 L at 296 K and 1.02 atm. Calculate the ma
Sonbull [250]

Answer:

there is 2% of hydrogen and 98% of nitrogen (mass percent)

Explanation:

assuming ideal gas behaviour

P*V=n*R*T

n= P*V/(R*T)

where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)

thus

n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles

since the number of moles is related with the mass m through the molecular weight M

n=m/M

thus denoting 1 as hydrogen and 2 as nitrogen

m₁+m₂ = mt (total mass)

m₁/M₁+m₂/M₂ = n

dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁

w₁/M₁+w₂/M₂ = n/mt

w₁/M₁+(1-w₁) /M₂ = n/mt

w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂)

replacing values

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)

and w₂= 1-w₁= 0.98 (98%)

thus there is 2% of hydrogen and 98% of nitrogen

4 0
3 years ago
2K + Cl2 —&gt; 2KCl <br><br> how many moles of KCl will be produced if you have 6.0 moles of K?
antiseptic1488 [7]

Answer:

6 moles

Explanation:

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Element used in bright flashlights
Mazyrski [523]
The element would be Neon. They are found in signs
8 0
4 years ago
(c) Which element is in Group V and in period 3​
Lorico [155]

Answer:

Phosphorus

Explanation:

Group V elements- Nitrogen, Phosphorous

period 3- Sodium, Magnesium, Aluminium, Silicon , Phosphorous, Sulphur, Chlorine and Argon

Group v and period 3 is phosphorus

6 0
3 years ago
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