The obligation of a medical coder to keep patients' medical information confidential is an example of the of ethics. <em><u>duty</u></em> theory.
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Answer:
The highly unstable pure sodium or potassium wants to lose an electron and this splits the water atom, producing a negatively charged hydroxide ion and hydrogen and forming an explosive gas that ignites.
Explanation:
Answer:
Option B.
Explanation:
- 2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
First we <u>convert 9.90 g of Pb(NO₃)₂ into moles</u>, using its molar mass:
- 9.90 g ÷ 331.2 g/mol = 0.0299 mol Pb(NO₃)₂
Then we<u> convert moles of Pb(NO₃)₂ into moles of PbO</u>, using the stoichiometric coefficients:
- 0.0299 mol Pb(NO₃)₂ * = 0.0299 mol PbO
Now we<u> convert 0.0299 mol PbO into grams</u>, using its molar mass:
- 0.0299 mol PbO * 223.2 g/mol = 6.67 g PbO
So <em>6.67 g is the theoretical yield</em>. With that in mind <u>we calculate the percent yield</u>:
- % yield = 5.51 / 6.67 * 100 % = 82.6%
So the correct answer is option B.
Answer:
Option a. 4 g of He
Explanation:
6.02×10²³ is the Avogadro's number. The amount of units that corresponds to 1 mol, in this case the units are molecules.
Let's find out which mass corresponds to 1 mol (mass / molar mass)
a. 4g / 4g/mol = 1 mol He
b. 14g / 6.94 g/mol = 2.01 mol Li
c. 80g /159.8 g/mol = 0.5 moles Br₂
d. 4g / 2g/mol = 2 mol H₂
Answer:
The correct answer is - B. dissolving → evaporation filtration → crystallisation
Explanation:
The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:
step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.
step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir
step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.
Step 4. leave the rest filtrate to crystallize.
Copper (II) Oxide {CuO (s)} + Dilute Sulfuric Acid {H2SO4 (aq)} → Copper (II) Sulphate {CuSO4 (s)} + Water {H2O}