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3 years ago

Rank the following quantities from smallest to largest: 5,200, dozen, pair,gross,ream.

Chemistry

1 answer:

Harrizon [31]3 years ago

6 0

5,200

dozen = 12

pair = 2

gross = 144

ream = 500

Pair, dozen, gross, ream, 5,200

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concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature

blondinia [14]

Answer:

82.0 mL

Explanation:

Step 1: Given data

Concentration of concentrated acid (C₁): 12.2 M

Volume of concentrated acid (V₁): ?

Concentration of dilute acid (C₂): 1.00 M

Volume of dilute acid (V₂): 1.00 L

Step 2: Calculate the required volume of the concentrated acid

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL

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2 years ago

Which equation is derived from the combined gas law?

Aloiza [94]

Answer:

The correct answer is V1/T1=V2/T2.

Explanation:

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3 years ago

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If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solutions should she m

Mice21 [21]

Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

Explanation:

Let the volume of 10% acid solution used to make the mixture = x L

So, the volume of 30% acid solution used to make the mixture = y L

Total volume of the mixture = x + y = 30 L .................. (1)

For 10% acid solution:

C₁ = 10% , V₁ = x L

For 30% acid solution :

C₂ = 30% , V₂ = y L

For the resultant solution of sulfuric acid:

C₃ = 25% , V₃ = 30 L

Using

C₁V₁ + C₂V₂ = C₃V₃

10×x + 30×y = 25×30

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x + 3y = 75 .................. (2)

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x = 7.5 L

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2 years ago

_Mg+_O2=_MgO Balance out this reaction above

Ira Lisetskai [31]

2 Mg + 1 O2 = 2 MgO.

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2 years ago

Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this

Sedbober [7]

Answer: The energy of one photon of the given light is $3.79\times 10^{-19}J$

Explanation:

To calculate the energy of one photon, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

$\lambda$ = wavelength of light = $525nm=5.25\times 10^{-7}m$ (Conversion factor: $1m=10^9nm$ )

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

Putting values in above equation, we get:

$E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J$

Hence, the energy of one photon of the given light is $3.79\times 10^{-19}J$

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2 years ago