Answer:
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
Explanation:
The activity series helps us to easily define whether or not a reaction will occur.
Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.
With the above information in mind, let us answer the questions given above.
Ag + NaNO₃ —> Na + AgNO₃
The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.
Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg
The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.
Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg
The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.
From the above illustration, only
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
Will occur.
Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar
Explanation :
Formula used :
![\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
The given molecule is, 
![\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B4%2B3-1%5D%3D3)
That means,
Bond pair = 3
Lone pair = 0
The number of electron pair are 3 that means the hybridization will be 
and the electronic geometry of the molecule will be trigonal planar.
Hence, the electron geometry (eg) and molecular geometry (mg) of is, trigonal planar and trigonal planar respectively.
Answer:
pKb = 10.96
Explanation:
Tartaric acid is a dyprotic acid. It reacts to water like this:
H₂Tart + H₂O ⇄ H₃O⁺ + HTart⁻ Ka1
HTart⁻ + H₂O ⇄ H₃O⁺ + Tart⁻² Ka2
When we anaylse the base, we have
Tart⁻² + H₂O ⇄ OH⁻ + HTart⁻ Kb1
HTart⁻ + H₂O ⇄ OH⁻ + H₂Tart Kb2
Remember that Ka1 . Kb2 = Kw, plus pKa1 + pKb2 = 14
Kb2 = Kw / Ka1 → 1×10⁻¹⁴ / 9.20×10⁻⁴ = 1.08×10⁻¹¹
so pKb = - log Kb2 → - log 1.08×10⁻¹¹ = 10.96
Answer:
Thus, the radius of the helium atom in nanometers is - 0.031 nm
Explanation:
Given that:-
The radius of the helium atom = 31 pm
Considering the conversion of length in pm to the length in nm as:-
1 pm = 0.001 nm
So,
Applying the above conversion factor in the radius of helium atom as:-
Radius = 
nm = 0.031 nm
<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>
The balanced chemical reaction is:
<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.
28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
