Question

Find the real solutions of the equation involving fractional exponents: (x+3)^3/2 −8=0

Answer 1

Answer:

$\boxed{x=1}$

Step-by-step explanation:

$(x+3)^{\frac{3}{2}}-8=0$

$(x+3)^{\frac{3}{2}}=8$

$(x+3)^{\frac{3}{2} \cdot 2}=8^2$

$(x+3)^{3}=64$

$x+3=\sqrt[3]{64}$

$x+3=\sqrt[3]{4^3}$

$x+3=4$

$x=1$