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KengaRu [80]
3 years ago
9

Anya makes a scale drawing of a bug. The scale of the drawing’s length to the actual bug’s length is 2 inches: 1/8 inch. The act

ual bug is 3/4 inch long. How long is Anya’s drawing of the bug.
Mathematics
1 answer:
ioda3 years ago
7 0
<h2>Hello!</h2>

The answer is: The Anya's drawing is 6 inches long.

Have a nice day!

<h2>Why?</h2>

To solve this problem, we need to consider the drawing's length with respect to the actual bug's size, so, the scale factor is:

2in:\frac{1}{8}in\\\\2x(in):\frac{3}{4}in

So, how long is Anya's drawing of the bug?

We can find it, using the following equation:

(2x)in=\frac{2in*\frac{3}{4}in}{\frac{1}{8}in}=\frac{\frac{6}{4}in}{\frac{1}{8}in}=\frac{\frac{3}{2}in }{\frac{1}{8}in}\\\\(2x)in=\frac{\frac{3}{2}in }{\frac{1}{8}in }=\frac{3}{2}in*\frac{8}{1}in=12in^{2}\\\\(2x)in=12in^{2} \\\\x=\frac{12in^{2} }{2in}=6in

Hence, the Anya's drawing is 6 inches long.

Have a nice day!

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Answer:

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Step-by-step explanation:

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where;

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In our case;

R=unknown

S=$20.50

C=$14.50

replacing;

R={(20.5-14.5)/14.5}×100

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A growth-mindset researcher plans to take an SRS of 200 teenagers from the population of teenagers in North America to see what
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Answer:

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Step-by-step explanation:

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For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

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This means that p = 0.75

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This means that n = 200.

What are the mean and standard deviation of the sampling distribution of p?

By the Central Limit Theorem

Mean \mu = p = 0.75

Standard deviation s = \sqrt{\frac{0.75*0.25}{200}} = 0.0306

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Step-by-step explanation:

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0.25

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Then;

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So, Y_1 and Y_2 are independent; then:

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3 years ago
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