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ryzh [129]
3 years ago
8

What statement best describes the kind of change that could have taken place

Physics
1 answer:
Anarel [89]3 years ago
5 0
In order to answer the question, we need to know what was there before
AND what was there after.  Is there a reason why you're concealing that
information ?

While you're at it, you might pass along the answer choices too.
You might be interested in
A vertical scale on a spring balance reads from 0 to 200 \rm{N}. The scale has a length of 10.0 \rm{cm} from the 0 to 200 \rm{N}
pav-90 [236]

Answer:

m = 12.05 kg

Explanation:

Spring constant in K, N/m

K = 200/10* 100

K = 2000 N/m

Angular Frequency = sqrt (Spring constant / (Mass )

ω = 2 π f

ω =  2π* 2.05 Hz = 12.8805 rad/s

ω^2 = Spring constant / Mass

Mass= Spring constant / ω^2

ω^2 = 165.907 rad^2/s^2

m = 2000 (N/m)/165.907 (rad^2/s^2)

m = 12.05 kg

8 0
3 years ago
A(n) ____________ image cannot be projected and forms where light rays appear to originate.
IrinaVladis [17]
A virtual image is the answer.
6 0
3 years ago
Read 2 more answers
Please Help Quick ASAP Hurry This is Physical Science
krok68 [10]

Answer:

Think it is C

Explanation:

Not sure!!!

6 0
3 years ago
All life that we know of is based on carbon. Carbon's ability to form many chemical bonds is an important characteristic that al
AlladinOne [14]
One answer I think would be Oxygen
5 0
3 years ago
Suppose an oven's radiation wavelength is 0.125 m. a container with 350.00 g of water was placed in the oven, and the temperatur
ivann1987 [24]
The heat (energy) needed to raise the temperature of the water is given by
Q=m C_S (T_f - T_i)=(350.0 g)(4.18 J/gC)(80C-20C)=87780 J

The wavelength of the radiation of the oven is \lambda=0.125 m, so the energy of a single photon of this radiation is
E=h \frac{c}{\lambda}=(6.6 \cdot 10^{-34}J) \frac{3\cdot 10^8 m/s}{0.125 m}=1.6 \cdot 10^{-24} J

So, the number of photons required to heat the water is the total energy absorbed by the water divided by the energy of a single photon:
N= \frac{Q}{E}= \frac{87780 J}{1.6\cdot 10^{-24}J}=  5.5 \cdot 10^{28} photons
8 0
3 years ago
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