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Yakvenalex [24]
3 years ago
10

cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your

answer in seconds, minutes, and hours
Physics
1 answer:
sp2606 [1]3 years ago
4 0

We have that the time in seconds, minutes, and hours is

t=1.083*10^{-4}s

T_{min}=1.805*10^{-6}min

T_{hours}=3.0083*10^{-8}hours

From the Question we are told that

Velocity v=13.0m/s

Distance d=120 km

Generally the equation for the Time  is mathematically given as

t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s

Therefore

T_{min}=1.083*10^{-4}s/60

T_{min}=1.805*10^{-6}min

And

T_{hours}=T_{min}/60

T_{hours}=3.0083*10^{-8}hours

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

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The density (mass divided by volume) of pure water is 1.00 g/cm^3 that of whole blood is 1.05 g/cm^3 and the density of seawater
Stells [14]

Answer:

a) 5000 g

b) 5250 g

c) 5150 g

Explanation:

For easier calculations, the formulas will be converted from g/cm³ to kg/m³, and then back when we're done.

Density of pure water is 1 g/cm³

1 g/cm³ = 1 * 0.001/0.000001

1 g/cm³ = 1000 kg/m³, and thus,

Density of pure blood

1.05 g/cm³ = 1050 kg/m³

Density of seawater

1.03 g/cm³ = 1030 kg/m³

Recall that, Density = mass / volume, and as such, mass = density * volume.

Converting our volume from L to m³

1 m³ = 1000 L, and as such

1 L = 0.001 m³

5 L = 0.005 m³

Mass of pure water = 1000 * 0.005

Mass of pure water = 5 kg

Mass of pure blood = 1050 * 0.005

Mass of pure blood = 5.25 kg

Mass of seawater = 1030 * 0.005

Mass of seawater = 5.15 kg

Converting these masses back to g, we have

Mass of pure water = 5 kg * 1000 g

Mass of pure water = 5000 g

Mass of pure blood = 5.25 kg * 1000 g

Mass of pure blood = 5250 g

Mass of seawater = 5.15 kg * 1000 g

Mass of seawater = 5150 g

6 0
3 years ago
A car covers a distance of 200m. If its velocity is 20 m/s, calculate the time taken. ​
Anvisha [2.4K]

Answer:

10 seconds

Explanation:

  • velocity=displacement/time
7 0
3 years ago
Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our
Gnom [1K]

Answer:

 f = v / 4L

the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

Explanation:

In wind instruments the wave speed must meet

          v = λ f

          λ = v / f

from v is the speed of sound that depends on the temperature

          v = v₀ \sqrt{1+ \frac{T [C]}{273} }

where I saw the speed of sound at 0ºC v₀ = 331 m/s  the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation

            (F -32) 5/9 = C

            76ºF = 24.4ºC

            45ºF = 7.2ºC

           

With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside

at T₁ = 24ºC               v₁ = 342.9 m / s

at T₂ = 7ºC                 v₂ = 339.7 m / s

To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change

              λ / 4 = L

              λ= 4L

              v / f = 4L

              f = v / 4L

Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

3 0
3 years ago
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