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3 years ago

7

The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by k(x)

= 9x – 2. Which expression represents the profit, (k – h)(x), of producing soccer balls?

1 answer:

a_sh-v [17]3 years ago

6 0

Answer:

(4x+4)

Step-by-step explanation:

h(x)=5x+6

k(x)=9x-2

(k-h)(x)= (9x-2-5x+6)

9x-5x=4x -2+6=4

(k-h)(x)= (4x+4)

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Cuál sería la respuesta a esto? La señora María obtuvo un préstamo de 5 millones otorgado por un banco, para devolver el préstam

Lubov Fominskaja [6]

Answer:

La señora María debe pagar 463.635 guaraníes por concepto de intereses,

Step-by-step explanation:

Se recomienda utilizar el modelo de interés compuesto puesto que la tasa de interés es constante y periódico, dado que se conoce el monto a pedir prestado, la tasa de interés y el número de anualidades, se obtiene el monto final. La cantidad de dinero a pagar es la diferencia entre ese resultado y el monto a ser prestado.

El modelo de interés compuesto es representado por la siguiente fórmula:

$C(t) =C_{o}\cdot (1+r)^{t}$ (1)

Donde:

$C_{o}$ - Cantidad de dinero a prestar, medida en guaraníes.

$r$ - Razón de interés interanual, adimensional.

$t$ - Anualidad, medida en años.

$C(t)$ - Cantidad de dinero asociada a la anualidad actual, medida en guaraníes.

Si sabemos que $C_{o} = 5.000.000$ , $r = 0.03$ y $t = 3$ , entonces la cantidad de dinero asociada al término del período de préstamo es:

$C(3) = 5.000.000\cdot (1+0.03)^{3}$

$C(3) = 5.463.635$

Finalmente, la cantidad de dinero a pagar por concepto de intereses es:

$\Delta C = 5.463.635-5.000.000$

$\Delta C = 463.635$

La señora María debe pagar 463.635 guaraníes por concepto de intereses,

3 0

3 years ago

(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^

Sedbober [7]

Hello,

a)
$I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\

= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\

=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\

= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\
= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\

$
$I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\
I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\
$

b)
$\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\
= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\
= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\




$

$\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\
= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\





$

c)

$I_n= \dfrac{n-1}{n} * I_{n-2} \\

I_{2n+1}= \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\
= \dfrac{2n}{2n+1} * I_{2n-1} \\
= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\
= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\

I_1=1\\

$

3 0

3 years ago

Plz help me with this

saul85 [17]

Your answer would be the second option, (-4,5).

We can find this by substituting in each point into the equation y < |x - 3| and seeing if it is true.

For the first one you get 1 < |2 - 1|. |2 - 1| = |-1| = 1, and 1 cannot be less than itself, so this is false.

For the second one you get 5 < |-4 - 3|. |-4 - 3| = |-7| = 7, and 5 is indeed less than 7, so this is correct.

I hope this helps!

7 0

3 years ago

Read 2 more answers

Hannah is 3 years older than twice her brother Joey’s age. Joey is 2 years old. How old is Hannah? Show all of your work!

DaniilM [7]

Answer:

7

Step-by-step explanation:

twice for joey's age so joeys age is 2 double that it will be 4 so 3+4=7

5 0

3 years ago

What is the slope of y=-4

VARVARA [1.3K]

Answer:

0

Step-by-step explanation:

It is 0 because the slope intercept form is y=mx+b right now you only have the y intercept which is the b of the equation. That means that your slope is non existence

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3 years ago