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vovangra [49]
3 years ago
14

How much energy is needed to melt 25.4 grams of l2

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer:

0.7824 KJ

Explanation:

Given data:

Mass of iodine = 25.4 g

Amount of heat required to melt = ?

Solution:

The heat of fusion of iodine is 7.824 Kj /mol

Number of moles of iodine = 25.4 g/ 254 g/mol

Number of moles of iodine = 0.1 mol

The amount of heat required to melt one mole of iodine is 7.824 Kj /mol

For 0.1 mol;

7.824 Kj /mol × 0.1 mol

0.7824 KJ

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When the following equation is balanced using the smallest possible integers, what is the number in front of the substance in bo
weeeeeb [17]

The balanced equation :

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

You just have to look for which element is in bold because the question is not clear

<h3>Further explanation</h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Al + Fe₃O₄→ Al₂O₃ + Fe

give a coefficient

aAl + Fe₃O₄→ bAl₂O₃ + cFe

O, left=4, right=3b⇒3b=4⇒b=4/3

Al, left=a, right=2b⇒a=2b⇒a=2.4/3⇒a=8/3

Fe, left=3, right=c⇒c=3

The equation becomes :

8/3Al + Fe₃O₄→ 4/3Al₂O₃ + 3Fe x3

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

7 0
3 years ago
What type of rays result in shorter days? (science)
OLEGan [10]

Answer:

verical rays

Explanation:

4 0
3 years ago
What is the difference between unconfined aquifers and confined aquifers?
Marta_Voda [28]

Answer:

A

Explanation:

Unconfined aquifers are those into which water seeps from the ground surface directly above the aquifer. Confined aquifers are those in which an impermeable dirt/rock layer exists that prevents water from seeping into the aquifer from the ground surface located directly above.

5 0
3 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
What happens to a gas that is enclosed in a rigid container when the temperature of the gas is increased?
yanalaym [24]
A) - heat makes particles move faster, which usually makes the substance as a whole expand, but if the gas cannot expand the pressure will increase instead
7 0
3 years ago
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