I would say c . isotope mass both varies in neutron numbers and its weighted by its relative abundance to give the average atomic mass. <span />
BaCl2 reacts with KOH forming KCl which is a salt and Ba(OH)2 which is the precipitate.
The initial UNBALANCED equation expressing this reaction would be:
BaCl2 + KOH .............> KCl + Ba(OH)2
Now, we need to balance this equation:
we have two moles of Cl as reactants and one mole only as product. Therefore, we will multiply the KCl in the product by 2 and the KOH in the reactants by 2.
This will balance the equation as follows:
BaCl2 + 2KOH ......> 2KCl + Ba(OH)2
Noticing this equation, we will find that:
The precipitate was formed due to the combination of the Ba2+ ion with 2 OH- ions as follows:
Ba2+ + OH- ............> Ba(OH)2
Answer:
88.92 grams of Ca(OH)₂ are required
Explanation:
Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.
In 2 L, we 'll have the double of moles, 1.2
Mol . molar mass = grams
1.2 mol . 74.1 g/m = 88.92 grams of solute
There are two things that could be done. The first is to increase the mass of the objects. The second is to decrease the distance between the center of masses of the objects.
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O
converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5
1 P and 2 oxygens.
PO2 -> the empirical formula
hope this help
