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ad-work [718]
3 years ago
11

The total pressure in a tank fill with a mixture of gasses : Oxygen, Helium, and Argon is 15.3 atm. The phe = 3.2 atm , Po= 7.4

atm what is the PAr in the tank?
Chemistry
1 answer:
Kisachek [45]3 years ago
8 0

Answer:

Partial pressure of Ar = 4.7 atm

Explanation:

Total pressure of a mixture of gases = Sum of partial pressure of each gas

This mixture contains: O₂, He and Ar.

Total pressure = 15.3 atm

Total pressure = Partial pressure O₂ + Partial pressure of He + Partial pressure of Ar

15.3 atm = 7.4 atm + 3.2 atm + Partial pressure of Ar

Partial pressure of Ar = 15.3 atm - 7.4 atm - 3.2 atm

Partial pressure of Ar = 4.7 atm

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Meteorologists use weather balloons to carry weather instruments high into the atmosphere. When it is first released at Earth’s
inessss [21]

The pressure of the gas used in the weather balloon increases to expand the balloon.

Explanation:

  • Weather balloons contain the boxes where the weather measurement instruments are present that is attached to the large balloon.
  • Weather balloon uses gases like Hydrogen or Helium. When the weather balloon rises to the atmosphere, the air pressure decreases. This leads to the increase in the pressure of hydrogen or Helium gas used in the weather balloon. This expands the balloon.
  • The gas particles hits the balloon container and generates the pressure. The increase of pressure thus helps the weather balloon to move in a constant speed through the atmosphere.
8 0
3 years ago
Prform the following operation and express the answer in scientific notation 6.0 x 10^3-2.310^3
Marrrta [24]

The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

<h3> What is scientific notation?</h3>

Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.

You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .

<h3>Why it is used? </h3>

There are two reasons to use scientific notation.

  • The first is to reveal honest uncertainty in experimental measurements.
  • The second is to express very large or very small numbers so they are easier to read.

Given,

= 6.0 x 10^3- 2.3 × 10^3

= (6.0 - 2.3) × 10^3

= 3.7 × 10^3

Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

learn more about scientific notation :

brainly.com/question/18073768

#SPJ1

3 0
2 years ago
What type of decay characterizes the change of radioactive nuclides to their respective daughter products?
tigry1 [53]
I believe the correct answer is the second option. The type of decay that characterizes the change of nuclides to their respective daughter products would be exponential decay. This type of decay is characterized by the decrease of quantity of a material according to the equation y=ab^x.
8 0
3 years ago
B. The highly toxic gas phosgene is produced by the reaction CO(g) + Cl2(g) COCl2(g), ΔH = –108 kJ/mol. Use this reaction to ans
galben [10]

Answer:

I. Increasing pressure will allow more frequent successful collision between particles due to the particles being closer together.

II. Rate of reaction increases due to more products being made; as increased pressure favours the exothermic side of the equilibrium.

III. Increasing temperature provides particles lots of (Kinetic) energy, for more frequent successful collision due to the particles moving at a faster rate than before. However, favouring the endothermic side of the equilibrium due to lots of energy required to break and form new bonds.

IV. Rate of reaction increases due to increase temperature favouring both directions of the equilibrium - causing products to form faster.

Hope this helps!

6 0
2 years ago
If earth is 1.50 x 10^8km from the sun what is the distance in Mm?
Readme [11.4K]

The distance of the earth to the sun in Mm = 1.5 x 10⁵

<h3>Further explanation</h3>

Given

The distance of the earth to the sun : 1.50 x 10⁸ km

Required

The distance in Mm

Solution

In converting units we must pay attention to the conversion factor.

the conversion factor :

1 kilometer(km) = 10⁻³ megameter(Mm)

So the distance conversion :

1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm

8 0
3 years ago
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