Answer:
This is the answer: The speed of a proton is about 5.0 × 10⁵ m/s
Explanation:
Because of the speeds of protons! :D
Answer:
life (N) of the specimen is 117000 cycles
Explanation:
given data
ultimate strength Su = 120 kpsi
stress amplitude σa = 70 kpsi
solution
we first calculate the endurance limit of specimen Se i.e
Se = 0.5× Su .............1
Se = 0.5 × 120
Se = 60 kpsi
and we know strength of friction f = 0.82
and we take endurance limit Se is = 60 kpsi
so here coefficient value (a) will be
a =
......................1
put here value and we get
a =
a = 161.4 kpsi
so coefficient value (b) will be
b =
b =
b = −0.0716
so here number of cycle N will be
N = ![(\frac{ \sigma a}{a})^{1/b}](https://tex.z-dn.net/?f=%28%5Cfrac%7B%20%5Csigma%20a%7D%7Ba%7D%29%5E%7B1%2Fb%7D)
put here value and we get
N = ![(\frac{ 70}{161.4})^{1/-0.0716}](https://tex.z-dn.net/?f=%28%5Cfrac%7B%2070%7D%7B161.4%7D%29%5E%7B1%2F-0.0716%7D)
N = 117000
so life (N) of the specimen is 117000 cycles
About 12 hours is the time between a morning high tide and the next high tide
Explanation:
The Earth’s rotation happens between two tidal bulges
The “periodic rise and fall” of the surface water levels of the ocean is called tides. The gravitational action and interaction on the earth by the sun and the moon causes these tides. Different regions of the World experiences different patterns of tides like the diurnal, semi-diurnal etc.
When there is one high and one low tide occurring on a lunar day, then it is diurnal pattern. Semi-diurnal pattern occurs when there are two equal high and low tides on a single lunar day.
Since the Earth’s rotation happens between two tidal “bulges” on each lunar day, the coastal areas can experience two high and two low tides in every 24 hours plus 50 minutes.
Accordingly the time between two high tides would be 12 hours plus 25 minutes. Similarly, the time gap between a high to low tide would be 6 hours plus 12.5 minutes.