Explanation:
(a) First, we will calculate the number of moles as follows.
No. of moles = ![\frac{\text{mass}}{\text{molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bmass%7D%7D%7B%5Ctext%7Bmolar%20mass%7D%7D)
Molar mass of helium is 4 g/mol and mass is given as 0.1 kg or 100 g (as 1 kg = 1000 g).
Putting the given values into the above formula as follows.
No. of moles = ![\frac{\text{mass}}{\text{molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bmass%7D%7D%7B%5Ctext%7Bmolar%20mass%7D%7D)
=
= 25 mol
According to the ideal gas equation,
PV = nRT
or, ![(P_{2} - P_{1})V = nR (T_{2} - T_{1})](https://tex.z-dn.net/?f=%28P_%7B2%7D%20-%20P_%7B1%7D%29V%20%3D%20nR%20%28T_%7B2%7D%20-%20T_%7B1%7D%29)
![(6.90 atm - 3.45 atm) \times 200 L = 25 \times 0.0821 L atm/mol K \Delta T](https://tex.z-dn.net/?f=%286.90%20atm%20-%203.45%20atm%29%20%5Ctimes%20200%20L%20%3D%2025%20%5Ctimes%200.0821%20L%20atm%2Fmol%20K%20%5CDelta%20T)
= 336.17 K
Hence, temperature change will be 336.17 K.
(b) The total amount of heat required for this process will be calculated as follows.
q = ![mC \Delta T](https://tex.z-dn.net/?f=mC%20%5CDelta%20T)
= ![100 g \times 5.193 J/g K \times 336.17 K](https://tex.z-dn.net/?f=100%20g%20%5Ctimes%205.193%20J%2Fg%20K%20%5Ctimes%20336.17%20K)
= 174573.081 J/K
or, = 174.57 kJ/K (as 1 kJ = 1000 J)
Therefore, the amount of total heat required is 174.57 kJ/K.
Acceleration is the rate of change in an object's velocity
Answer:
Gold Has A Higher Resistance Than Copper. The Sample Of Gold Is Thinner Than The Sample Of Copper. Electrons In Gold Are More Likely To Be Scattered Than Electrons In Copper At Room Temperature When they are exelerated by the same electric field.
Explanation:
OzsnuhgnowgnwrfoqingoiwrgWWR KEFQF QEFI FBI O8QE VU F8EINFOQIHWJ OU JN K kjbJ IUJ j osd sfljvbwj 9 oirs jf bhfb wjsf jfow vj isfobsfjb io jio ofsjb
Answer:
![a=500m/s^2](https://tex.z-dn.net/?f=a%3D500m%2Fs%5E2)
Explanation:
We need only to apply the definition of acceleration, which is:
![a=\frac{v_f-v_i}{t_f-t_i}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_f-v_i%7D%7Bt_f-t_i%7D)
In our case the final velocity is
, the initial velocity is
since it departs from rest, the final time is
and the initial time we are considering is ![t_i=0s](https://tex.z-dn.net/?f=t_i%3D0s)
So for our values we have:
![a=\frac{10m/s-0m/s}{0.02s-0s}=500m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B10m%2Fs-0m%2Fs%7D%7B0.02s-0s%7D%3D500m%2Fs%5E2)