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Nutka1998 [239]
3 years ago
6

Hi please help me I'm in the middle of a test and I don't want to get grounded

Mathematics
2 answers:
Verizon [17]3 years ago
7 0

Answer:

A.

8(3j - 2)

lawyer [7]3 years ago
4 0

Answer:

8(3j-2)

Step-by-step explanation:

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Through which pairs of points is the slope negative? Select all that apply. a. (3, 6) and (10, 6)
xeze [42]
Trial and error on this one try each pair till you find negative slopes
C and D
5 0
3 years ago
An item is regularly priced at 85$. It is on sale for 80% off the regular price. How much is discounted from the regular price?
laila [671]

$68 is discounted from the regular price.

To find this, you first divide 80% by 100 to get 0.8 (the decimal form of the percentage). Then, simply multiply 0.8 by 85 (or vise verse) to get $68. Since the question is asking for how much is discounted from the regular price, the final answer would be $68.

I hope this helps!

4 0
3 years ago
Answer plz asap.......<br><br><br><br><br><br><br>​
dangina [55]
Im not sure but I’ll go with c :)
5 0
2 years ago
Find the area of the shaded region
xxTIMURxx [149]

Answer:

25.12

Step-by-step explanation:

8π = P

3 0
3 years ago
2. Consider the circle x² + y2 = 1, given in figure. Let OP makes an angle 30° with the x axis.
PolarNik [594]

The equation of the tangent line to the circle passing through the point P is; y = (1/√3)x ± 2/√3

<h3>How to find the equation of the tangent?</h3>

I) We are given the equation of the circle as;

x² + y² = 1

Since angle of inclination is 30°, then slope is;

m = tan 30 = 1/√3

Then equation of the tangent will be;

y = (1/√3)x + c

Put  (√3)x + c into the given circle equation to get;

x² + ((1/√3)x + c)² = 1

x² + ¹/₃x² +  (2/√3)cx + c² = 1

⁴/₃x² +  (2/√3)x + (c² - 1) = 0

Since we need to find value of c for equation to become tangent, then the above quadratic equation must have real and equal roots.

Thus;

((2/√3)c)² - 4(⁴/₃)(c² - 1) = 0

⁴/₃c² - ¹⁶/₃(c² - 1) = 0

⁴/₃c² - ¹⁶/₃c² + ¹⁶/₃ = 0

4c² = ¹⁶/₃

c² = ⁴/₃

c = √⁴/₃

c = ±²/√3

Thus, equation of tangent is;

y = (1/√3)x ± 2/√3

II) Radius from the given equation is 1. Thus, we will use trigonometric ratio to find the x and y intercept;

x-intercept is at y = 0;

0 = (1/√3)x ± 2/√3

-(1/√3)x = ±2/√3

Intercept is positive. Thus;

x = (2/√3)/(1/√3)

x = 1

y - intercept is positive at x = 0;

y = (1/√3)0 ± 2/√3

y = 2/√3

Read more about Equation of tangent at; brainly.com/question/17040970

#SPJ1

6 0
1 year ago
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