Hydroxylamine in water: HONH₂(aq) + H₂O(l) ⇄ HONH₃⁺(aq) + OH⁻(aq).
Hydroxylammonium nitrate in water: HONH₃NO₃(aq) → OHNH₃⁺(aq) + NO₃⁻(aq).
1) with positive hydrogen ions (protons) react base and gives weak conjugate acid:
H⁺(aq) + HONH₂(aq) ⇄ HONH₃⁺(aq).
2) with hydroxide anions react acid and produce weak base and weak electrolyte water:
HONH₃⁺(aq) + OH⁻(aq) ⇄ HONH₂(aq) + H₂O(l).
Answer:The masses of the reactants and products formed are not included in the question, so we cannot determine the percentage yield of water without knowing the yields of other substances.
However the formulae for percentage yield is;
Percentage yield=experimental yield/theoretical yield X 100
Answer:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Explanation:
There are many ways to balance a chemical equation. In this case, I will show you the algebraic method:
The first step is assign a letter to each compound:
a Fe₂O₃ + b CO → c Fe + d CO₂
Then, you must write the balance equations for each atom, thus:
<em>Fe: 2a = c</em>
<em>C: b = d</em>
<em>O: 3a + b = 2d</em>
The last step is assign a value to a letter. I, for example, will say that <em>a is 1, </em>and then find the values for the others letters, thus:
<em>Fe: 2a = c </em>if <em>a=1; c=2</em>
<em>O: 3a + b = 2d </em>if <em>a=1 → 3+b = 2d</em>
As b = d → <em>3+d = 2d; 3 = 2d - d; </em>3=d and 3=b
Thus, the balanced equation is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
I hope it helps!
