1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
3 years ago
5

What is the absorbance of the permanganate in the diluted waste solution?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
7 0
<span>Not to be confused with tetration. This article is about volumetric titration. For other uses, see Titration (disambiguation). Acid–base titration is a quantitative analysis of concentration of an unknown acid or base solution. Titration, also known as titrimetry,[1] is a common laboratory method of quantitative chemical analysis that is used to determine the unknown concentration of an identified analyte. Since volume measurements play a key role in titration, it is also known as volumetric analysis. A reagent, called the titrant or titrator[2] is prepared as a standard solution. A known concentration and volume of titrant reacts with a solution of analyte or titrand[3] to determine concentration. The volume of titrant reacted is called titration volume</span>
You might be interested in
You want to place a piece of glass tubing into a ruber stopper after the tubing has been fire polished and cooled. This is best
igor_vitrenko [27]

Answer:

All of the above

Explanation:

This is correct

4 0
3 years ago
What is N? (Needed electrons)
lianna [129]
Do you know what is meant by needed? does it mean lone pairs?
8 0
3 years ago
1.2 moles of (NH4)3PO3
Aleks04 [339]
1.2 moles of (nph4)3po3 is.......159.6 grams
3 0
3 years ago
Convert 205 L to ul.
Sloan [31]

Answer: 205000000 microliter

Hope this helps!

8 0
3 years ago
Read 2 more answers
Answer and work for this problem
MArishka [77]
We can write the balanced equation for the synthesis reaction as 
     H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
     mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) * 
                           (2.02 g H2 / 1 mol H2)                        
                        = 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
     mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
                             (70.91 g Cl2 / 1 mol Cl2)
                          = 142.4 g Cl2 

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.
6 0
3 years ago
Other questions:
  • Which of the following characteristics is fixed, or definite, for all states of matter?
    6·2 answers
  • At room temperature, 20ÁC, water (H2O) is a liquid and oxygen (O2) is a gas. Based on kinetic molecular theory, which answer bes
    6·1 answer
  • Avogadro's number refers to ___. the maximum number of electrons that all of an atom's energy levels can accommodate the number
    14·2 answers
  • This question has multiple parts. work all the parts to get the most points. one method for preparing a nitrile is the dehydrati
    9·1 answer
  • Use the free energies of formation given below to calculate the equilibrium constant (K) for the following reaction at 298 K. 2
    15·1 answer
  • 2Ag + H2S ➞ Ag2S + H2
    6·2 answers
  • What is true of a compound?
    6·2 answers
  • In a particular electroplating process, the metal being plated has a +4 charge. If 861.8 C of charge pass through the cell, how
    14·1 answer
  • Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 37g of hydrogen chloride?
    9·1 answer
  • The process of determining the composition of a sample by conducting chemical tests is called qualitative analysis.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!