Answer:
The correct answer is B the tertiary halides reacts faster than primary halides.
Explanation:
During SN2 reaction the nucleophile attack the alkyl halide from the opposite side resulting in the formation of transition state in which a bond is not completely broken or a new bond is not completely formed.
After a certain period of time the nucleophile attach with the substrate by substituting the existing nuclophile.
An increase in the bulkiness in the alkyl halide the SN2 reaction rate of that alkyl halide decreases.This phenomenon is called steric hindrance.
So from that point of view the that statement tertiary halides reacts faster that secondary halide is not correct.
The third one because temperature is being used, so a meter stick wouldn’t make sense. You aren’t measuring the length of anything physically. A stopwatch measures time, which is what they are showing in the chart, so the third one is the only one that makes sense.
I think external forces acting on an object may include friction, gravity, normal force, drag, tension, or a human force due to pushing or pulling can be represented by a free body diagram.
Hello,
Well,You have to understand pretty much everything,So look,If you know the number of protons or electron then you will know its atomic number,and if you know the number of protons and neutrons then you will know the mass of the element.So yeah,this is basically all you need to know to understand the unified structure of atom to help you better understand an element that was unfamiliar to you!
I truly hope this helps
The hybridization for the Br in BrO4⁻ is 
. So, the correct option is (e).
In chemistry, the idea of combining atomic orbitals to create new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) is known as orbital hybridisation (or hybridization). These new hybrid orbitals are suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Because more directional hybridised orbitals result in higher overlap when creating bonds, stronger bonds are formed, which favours the hybridization of orbitals. When hybridization takes place, this leads to more stable molecules.
One s orbital and three p orbitals combine to form four orbitals, each of which has a 25% s character and a 75% p character. This process is known as hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.
Learn more about hybridization here:
brainly.com/question/12207339
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