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goblinko [34]
3 years ago
7

To create hydrogen and oxygen from water, you would need to perform which type of reaction?

Chemistry
2 answers:
Murrr4er [49]3 years ago
6 0
B. Decomposition is the correct answer~
Lana71 [14]3 years ago
6 0

Answer is: B. Decomposition.

Decomposition is reaction where one substance is broken down into two or more simpler substances.

Electrolysis of water is the decomposition reaction, because from one molecule (water) two molecules (hydrogen and oxygen) are produced.

Water is separeted into two molecules:

Reaction of reduction at cathode: 2H⁺(aq) + 2e⁻ → H₂(g).

Reaction of oxidation at anode: 2H₂O(l) → O₂(g) + 4H⁺(aq) + 4e⁻.

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1 A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circul
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The correct answer to this question is that the length of 14 is it’s half Which would be 7
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2 years ago
What does not add co2 to the atmosphere
marissa [1.9K]

Answer:

Abiotic objects

Ex. bed, table, lamp, chair, blanket, etc.

Abiotic means Non-living.

7 0
2 years ago
Initially a beaker contains 225.0 ml of a 0.350 M MgSO4 solution. Then 175.0 ml of water are added to the beaker. Find the conce
Salsk061 [2.6K]
Final volume is 400 mL

<span>The moles in MgSO4 is 0.00788 </span><span>mL
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8 0
4 years ago
Read 2 more answers
4. A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic aci
kupik [55]

Answer:

2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.

Explanation:

We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.

Now we devise the following reasoning:

If          18 g of phthalic acid are dissolved in 100 mL of water at 99 °C

Then   0.5 g of phthalic acid are dissolved in X mL of water at 99 °C

X = (0.5 × 100) / 18 = 2.77 mL of water

7 0
3 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
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