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3 years ago

Starting billions of years ago, in what way did algae change the atmosphere

Chemistry

1 answer:

ikadub [295]3 years ago

7 0

Answer:

Option (C)

Explanation:

In the primitive world, about billions of years back, the initially formed organisms such as algae, were responsible for the production of large amount of oxygen in the atmosphere. This was possible by these algae, as they were able to carry out the process of photosynthesis, where the food is synthesized in the presence of sunlight, water and carbon dioxide (CO₂), and in return, it generates food and oxygen, on which the organisms are dependent on.

Thus, these algae were responsible for the changes in the atmosphere, by converting carbon dioxide (CO₂) into oxygen.

So, the correct answer is option (C).

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If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o

ddd [48]

Answer : The mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of $O_2$

$\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol$

Now we have to calculate the moles of $O_2$ in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

$V\propto n$

or,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

where,

$V_1$ = initial volume of gas = 6.21 L

$V_2$ = final volume of gas = 30.3 L

$n_1$ = initial moles of gas = 0.16 mol

$n_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}$

$n_2=0.781mol$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

Molar mass of $O_2$ = 32 g/mol

$\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g$

Therefore, the mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0

3 years ago

Find the grams of iron in 79.2 g of Fe2O3.

Setler79 [48]

First you find the RFM (Relative Formula Mass) of Fe2O3
Fe2 = 56 x 2
= 112
O3 = 16 x 3
= 48

112 + 48 = 160

Moles = mass/RFM
   = 79.2/160
   =0.495

Then you rearrange the formula
Mass= moles x RFM
      = 0.495 x 112
      = 55.44 g
(To find mass of Iron have to use RFM of total iron in the substance example Fe2 ^^)

3 0

2 years ago

8. What is a cell that does not have a nucleus or other membrane-bound organelles?

Natali [406]

Answer: The prokaryotic cell does not have a nucleus!

Explanation:

3 0

2 years ago

True or false

kolbaska11 [484]

Answer:

true

Explanation:

calculating the average atomic

7 0

2 years ago

Montrel takes a trip to Central America during the winter. He finds out that the temperature in Central America is about the sam

wolverine [178]

Answer:

Explanation

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6 0

3 years ago