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Anna [14]
2 years ago
15

How much calcium can be recovered from 75.0g of calcium fluoride

Chemistry
1 answer:
7nadin3 [17]2 years ago
3 0

38.46g

Explanation:

Given parameters:

Mass of CaF₂ = 75.0g

Unknown:

Mass of calcium that can be recovered = ?

Solution:

This is a mass percentage problem and we need to solve it accordingly.

To solve this problem;

Find the molar mass of  CaF₂

Find the ratio between the molar mass of Ca and that of  CaF₂

Multiply by the given mass

Molar mass of  CaF₂ = 40 + (2 x 19) = 78g/mol

Mass of calcium = \frac{40}{78} x 75 = 38.46g

learn more:

Mass percentage brainly.com/question/8170905

#learnwithBrainly

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Use lewis theory to determine the formula for the compound that forms between sr and se
katen-ka-za [31]

\text{Sr}\text{Se}

<h3>Explanation</h3>

The Lewis Theory predicts the way atoms form bond based on their numbers of valence electrons. Atoms gain or lose electrons as they seek to achieve either a complete eight-electron valence shell or an empty shell, exposing the inner eight-electron shell. Both electron configurations are stable and are known as "octets". However, atoms tend to prefer the configuration with the minimum number of electron transfers.

Strontium (Sr) is found in group 2 (II A) of a modern periodic table. A neutral atom of strontium has two valence electrons in its valence shell.

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n(\text{Sr, atoms}) : n(\text{Se, atoms}) \\= n(\text{Sr, electrons lost}) : n(\text{Se, electrons gained}) \\= 1:1

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Sr atoms have lost electrons. Accordingly, they carry positive charges and shall be written at the beginning of the formula.

Se atoms have gained electrons. Accordingly, they carry negative charges and shall be placed to the end of the formula.

Thus the chemical formula: \text{Sr}\text{Se}

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