Thus the value of [OH⁻] calculated is = 3.3 × 10⁻⁶ M
<u>Explanation:</u>
Given:
Concentration of H₃O⁺ = 3.3 × 10⁻⁹ M
To Find:
Concentration of OH⁻ ion = ?
Solution:
From the
value, and the concentration of H⁺ ion, we can find the concentration of hydroxyl ions, as
is the product of the concentration of H⁺ and OH⁻ ions. We have the concentration of hydronium ion or H⁺ ion and
value, dividing
by the H⁺ ion concentration, we will get the concentration of OH⁻ ion as,
= [H₃O⁺] × [OH⁻]
= 3.0 × 10⁻⁹ × [OH⁻]
Now we have to divide as,
[OH⁻] =
= 3.3 × 10⁻⁶ M
Answer:
This question is asking to calculate the molarity of the solution based on the information provided.
The answer is 2.94M
Explanation:
Molarity of Ca(OH)2 solution = number of moles (n) ÷ volume (V)
Using the formula below to calculate number of moles of Ca(OH)2.
mole = mass/molar mass
Molar mass of Ca(OH)2 = 74 g/mol
mole = 74g/74g/mol
mole = 1mol
Volume of Ca(OH)2 solution = 340ml = 340/1000 = 0.340 L
Molarity = 1/0.340
Molarity = 2.94M
Hey there,
<span>When the volume of a container of gas changes by a certain factor at a constant temperature, the pressure doubles. By what factor does the container’s volume change?
When the volume of a container of gas changes, this means that </span>
![\boxed{ The \ pressure \ will \ increase.}](https://tex.z-dn.net/?f=%5Cboxed%7B%20The%20%5C%20pressure%20%5C%20will%20%5C%20increase.%7D)
. And this means, the pressure will get stronger and double it's self.
<span>
I hope this can help you!
~Jurgen</span><span>
</span>
B- Oil spills can harm the environment
The grams of calcium phosphate that can be produced when 89.3 grams of calcium chloride reacted with excess sodium phosphate is
83.08 grams of calcium phosphate
<u><em>calculation</em></u>
Step 1: write a balanced chemical equation
3CaCl₂ + 2Na₃Po₄ →6NaCl + Ca₃(PO₄)₂
step 2: find the moles of CaCl₂
moles = mass÷ molar mass
from periodic table the molar mass of CaCl₂ = 40 +( 2 x 35.5) =111 g/mol
moles = 89.3 g÷111 g/mol = 0.805 moles
Step 3: use the mole ratio to determine the moles of Ca₃(PO₄)₂
CaCl₂: Ca₃(PO₄)₂ is 3:1 therefore the moles of Ca₃(PO₄)₂ =0.805 x 1/3 =0.268 moles
Step 4: find mass of Ca₃(PO₄)₂
mass = moles x molar mass
from periodic table the molar mass of Ca₃(PO₄)₂ = (40 x3) +[ 31 +(16 x4)]2 =310 g/mol
mass is therefore =0.268 moles x 310 g/mol =83.08 grams