The ratio of linear dimensions (side lengths) is the square root of the ratio of areas.
√1 : √4 = 1 : 2
The best choice is ...
B. 1:2
Answer:
x
=
6
,
−
5
Step-by-step explanation:
Move x
to the left side of the equation by subtracting it from both sides. x^
2
−
30
−
x
=
0
x2-30-x=0
Use the quadratic formula to find the solutions.
−
b
±
√
b
2
−
4
(
a
c
)/
2
a
-b±b2-4(ac)/2a
Substitute the values
a
=
1 , b
=
−
1 , and c
=
−
30
into the quadratic formula and solve for x
x
.
1
±
√
(
−
1
)
2
−
4
⋅
(
1
⋅
−
30
)/
2
⋅
1
Simplify.
x
=
1
±
11/
2
The final answer is the combination of both solutions.
x
=
6
,
−
5
<span>a, để pt có nghiệm thì denta ≥ 0 <=> (3-m)^2 - 4( 3-2m) ≥ 0 <=> m^2 +2m-3 ≥ 0 ( ^ là mũ)
giải bpt mới tìm được đó ta đc : m ≤ -3 hoặc m ≥ 1
b, * Xét m-1=0 <=> m=1 => thay m=1 vào pt thì pt có 1 nghiệm là 1/8 (1)
* Xét m-1 ≠ 0 <=> m ≠ 1
=> pt có nghiệm khi denta' ≥ <=> (m+3)^2 - (m-1)(-m+2) ≥0 <=> 2m^2 +3m+11 ≥ 0 (*)
-> bpt (*) có denta < 0 nên nó luôn đúng với mọi m ≠1 -> denta của pt đã cho luôn > 0 với mọi m ≠ 1 (2)
từ (1) (2) => với mọi m pt luôn có nghiệm </span>
They meet at a point
Step-by-step explanation:
trust me
Answer: It is not possible for Janet to have won 10 games.
Step-by-step explanation:
Let be "x" the number of games Janet won.
We know that Nadia has won twice the number of games Janet has and the sum of the games Nadia and Janet have won together is 24.
Then, we express this situation with this equation:
So, let's check if it is possible for Janet to have won 10 games. Substitute 
into the expression:
Therefore, it is not possible for Janet to have won 10 games.
