Will use A and B in place of a and b for clarity.
Let x=number of individuals away from A, including A & B
Without loss of generality, assume A is seated in seat #1.
Then B is seated at 2,3,4,5 with equal probability.
Half of the time B is seated at 2 or 5, each of which is next to A, therefore x=2
The other half of the time B is seated at 3 or 4, each of which is separated from A by one seat, then x=3.
The expected number of individuals
E[X]=sum (x*P(x))
=2*(1/2)+3(1/2)
=2.5
So the expected number of individuals to handle the message is 2.5.
Answer:
140,120
Step-by-step explanation:
sum of angles in a quadrilateral =360
sum of the 1st two angles=60+40=100
360-100=260
the ratio of the remaining angles 7:6
therefore:
=140
for the second angle
260-140=120
Answer:
x=-7
Step-by-step explanation:
C is your answer. The coefficient on the x value is always a stretch factor.
