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kirill [66]
3 years ago
11

Why Saturn has rings around it?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
5 0
The rings of Saturn were made from one of Saturn's moons being destroyed and knocked into orbit. The remnants of the moon rotating in the orbit created the icy rings that orbit Saturn today.
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Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the
Anvisha [2.4K]

Answer:

The temperature change is 80°C

Explanation:

Heat absorbed by the melting ice (Q) = mL = 312×336 = 104,832 J

∆T = Q/mC = 104,832/312×4.2 = 80°C

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3 years ago
A mixture containing particles that settle our if left undisturbed is a​
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The answer is Suspension

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4 years ago
An elements reactivity is determined by its number of....
erastovalidia [21]
protons because of the atomic number
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3 years ago
Help please. 15.0 moles of gas are in a 3.00L tank at 23.4∘C . Calculate the difference in pressure between methane and an ideal
CaHeK987 [17]
Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT.  Substituting  a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>
3 0
3 years ago
The following are products in the chemical reaction shown below.
scoundrel [369]

Answer:

C₆H₁₂O₆ and O₂

Explanation:

To know which option is correct, it important that we know the concepts of chemical equation .

A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.

The reactant is located on the left side and the product is located on the right side.

Reactant —> Product

With the above information, let us answer the question given above.

6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂

The products are located on the right side of the equation.

Thus, the products of the reaction is C₆H₁₂O₆ and O₂

8 0
3 years ago
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