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seraphim [82]
4 years ago
11

What season does the sourtther hempishere experience when it is away from the sun?

Chemistry
1 answer:
kakasveta [241]4 years ago
4 0
I believe Winter is <span>your answer.</span>
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6 trillion quadrant
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3 years ago
A a black metal measures 2 cm x 3 cm x 2.5 cm if it's much is 67.5 grams calculate its density​
liraira [26]

Answer:

d=4.5  g/cm³

Explanation:

v=l x w x h

v=2 x 3 x 2.5

v=15 cm³

d=m/v

d=67.5/15

d=4.5  g/cm³

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3 years ago
Another term for natural radioactive decay into another element is
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The process of unstable (or radioactive) atoms becomes stable by emitting radiation. This event over time is called radioactive decay. Alpha decay results in the loss of two protons and two neutrons from the nucleus

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What coefficients should be added in order to make this a balanced equation?
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6 0
4 years ago
The partial pressure of cartbon dioxide in the atmgsphere is 0239 toer Caiculate the partial pressure in mm He and atm Rpund eac
Verizon [17]

Answer :

The pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

The pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

Explanation :

The conversion used for pressure from torr to mmHg is:

1 torr = 1 mmHg

The conversion used pressure from torr to atm is:

1 atm = 760 torr

or,

1torr=\frac{1}{760}atm

As we are given the pressure of carbon dioxide in the atmosphere 0.239 torr. Now we have to determine the pressure of carbon dioxide in the atmosphere in mmHg and atm.

<u>Pressure in mmHg :</u>

As, 1torr=1mmHg

So, 0.239torr=\frac{0.239torr}{1torr}\times 1mmHg=0.239mmHg

Thus, the pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

<u>Pressure in atm:</u>

As, 1torr=\frac{1}{760}atm

So, 0.239torr=\frac{0.239torr}{1torr}\times \frac{1}{760}atm=3.14\times 10^{-4}atm

Thus, the pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

3 0
3 years ago
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