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allochka39001 [22]
3 years ago
7

Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the

melting ice and then use q=mCΔTq=mCΔT to calculate the temperature change of the 312 gg of water.
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

The temperature change is 80°C

Explanation:

Heat absorbed by the melting ice (Q) = mL = 312×336 = 104,832 J

∆T = Q/mC = 104,832/312×4.2 = 80°C

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This is because the fungi and bacteria are the decomposer, and their job is to decompose dead organism.

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calculate the (m/v) of nacl of a solution made by diluting 25.0 ml of a 7.50 (m/v)% NaCl solution to a total volume of 75.00 ml
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c

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M=<br> V=432.6 mL<br> D=8.4 g/ml
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Answer:

Explanation:

M=D times V

Answer-3,633.84g

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3 years ago
On the basis of the Ksp values below, what is the order of the solubility from least soluble to most soluble for these compounds
Viktor [21]

Answer:

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

Explanation:

The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:

Ksp = (A) (B) where A and B are the molar solubilities = s²  (for compounds with 1:1  ratio).

It follows then  that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:

Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.

Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹²  with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of  the ratio of ions 2:1 in Ag2CO3,  so the answer is not obvious. But since we know that

Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋

Ksp Ag2CO3  = 2s x s = 2 s² =  8.0 x 10-12

s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶

And for AgCl

AgCl  ⇄ Ag⁺ + Cl⁻

Ksp = s² = 1.8 x 10⁻¹⁰  ∴ s = √ 1.8 x 10⁻¹⁰   = 1.3 x 10⁻⁵

Therefore, AgCl is more soluble than Ag₂CO₃

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

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3 years ago
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A sample of gas has a volume of 75.0 mL at 30.0 psi. Determine the pressure of the gas if its volume is changed to 15 mL and its
Assoli18 [71]

Answer:

5.995 psi

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0.075x = 0.0306

x = 0.408

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