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Firlakuza [10]
3 years ago
10

Help please. 15.0 moles of gas are in a 3.00L tank at 23.4∘C . Calculate the difference in pressure between methane and an ideal

gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2 and b=0.0430 L/mol..
Chemistry
1 answer:
CaHeK987 [17]3 years ago
3 0
Using PV=nRT or the ideal gas equation, we substitute n= 15.0 moles of gas, V= 3.00L, R equal to 0.0821 L atm/ mol K and T= 296.55 K and get P equal to 121.73 atm. The Van der waals equation is (P + n^2a/V^2)*(V-nb) = nRT.  Substituting  a=2.300L2⋅atm/mol2 and b=0.0430 L/mol, P is equal to 97.57 atm. The difference is <span>121.73 atm- 97.57 atm equal to 24.16 atm.</span>
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A chemist prepares a solution of calcium bromide by weighing out 0.607g of calcium bromide into a 450ml volumetric flask and fil
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Answer:

0.00676 M

Explanation:

A chemist prepares a solution of calcium bromide by weighing out 0.607g of calcium bromide into a 450ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Mass of calcium bromide (solute): 0.607 g

Volume of solution: 450 mL

Step 2: Calculate the moles corresponding to 0.607 g of calcium bromide

The molar mass of CaBr₂ is 199.89 g/mol.

0.607 g × 1 mol/199.89 g = 0.00304 mol

Step 3: Convert the volume of solution to liters

We will use the conversion factor 1 L = 1000 mL.

450 mL × 1 L/1000 mL = 0.450 L

Step 4: Calculate the molar concentration of calcium bromide

The molarity of the solution is:

M = moles of solute / liters of solution

M = 0.00304 mol / 0.450 L

M = 0.00676 M

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3 years ago
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Each electron configuration has 4 quantum numbers, namely n, l, ml, and ms

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