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kaheart [24]
2 years ago
5

As a sample's temperature increases, which two factors also increase? A. Particle speed B. Particle kinetic energy C. Particle b

oiling point D. Particle size
NEED ANSWERS ASAP PLZ
Chemistry
2 answers:
jeyben [28]2 years ago
8 0

Answer:

C.

Explanation:

It’s particle boiling point because the atoms are moving fast around the particle as possible, so there for its C..

OLga [1]2 years ago
4 0

Answer:

B

Explanation:

the kinetic energy will change

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Calculate the pH of a solution that has a [OH−] of 2.6 × 10^−6 M.
TiliK225 [7]

Answer:

A. 8.4

Explanation:

[OH⁻] = 2.6 × 10⁻⁶               Take the negative log of each side

-log[OH⁻] = pOH = 5.59     Apply the pH/pOH relation

pH + pOH = 14.00               Insert the value of pOH

pH + 5.59 = 14.00               Subtract 5.59 from each side

pH = 14.00 -5.59 = 8.41

7 0
2 years ago
How much 10.0 M HNO must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH
Naya [18.7K]

Explanation:

It is given that molarity of acetic acid = 0.0100 M

Therefore, moles of acetic acid = molarity of acetic acid × volume of buffer

            Moles of acetic acid = 0.0100 M × 1.00 L

                                              = 0.0100 mol

Similarly, moles of acetate = molarity of sodium acetat × volume of buffer

                                           = 0.100 mol

When HNO_{3} is added, it will convert acetate to acetic acid.

Hence, new moles acetic acid = (initial moles acetic acid) + (moles HNO_{3})

                                                = 0.0100 mol + x

New moles of sodium acetate = (initial moles acetate) - (moles HNO_{3})

                                        = 0.100 mol - x

According to Henderson - Hasselbalch equation,

           pH = pK_{a} + log\frac{[conjugate base]}{[weak acid]}

             pH = pKa + log\frac{(new moles of sodium acetate)}{(new moles of acetic acid)}

           4.95 = 4.75 + log\frac{(0.100 mol - x)}{(0.0100 mol + x)}

       log\frac{(0.100 mol - x)}{(0.0100 mol + x)}  = 4.95 - 4.75

                                            = 0.20

\frac{(0.100 mol - x)}{(0.0100 mol + x)}  = antilog (0.20)

                                           = 1.6

Hence,    x = 0.032555 mol

Therefore, moles of HNO_{3} = 0.032555 mol

volume of HNO_{3} = \frac{moles HNO_{3}}{molarity of HNO_{3}}

                                = \frac{0.032555 mol}{10.0 M}

                                 = 0.0032555 L

or,                             = 3.25           (as 1 L = 1000 mL)

Thus, we can conclude that volume of HNO_{3} added is 3.26 mL.

5 0
2 years ago
What are the radical groups present in polar solvents?
Anni [7]

Answer: Polar solvents

Explanation:

6 0
2 years ago
When atoms come together, there is _______ between the positive nucleus and the negative electron clouds
vova2212 [387]

My guess is attraction.

3 0
3 years ago
What evidence is there that energy is conserved?
Tems11 [23]
The law of conservation 

Hope this helps

~ Jordan ~
5 0
3 years ago
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