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3 years ago

Why is it so important to record all the data in a science experiment

Physics

1 answer:

MissTica3 years ago

8 0

Answer:

It is important to record all the data in a science experiment because that is what will help you to present your data, get results, and repeat your experiment. It can also help other scientists who are planning to repeat the experiment to set a base line and have an understanding of the process before completing the experiment.

Explanation:

as stated above.

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The radius of an atom of krypton (kr) is about 1.9 å. (a) express this distance in nanometers (nm). nm express this distance in

I am Lyosha [343]

Note:
1 A (armstrong) = 10⁻¹⁰ m
1 nm (nanometer) = 10⁻⁹ m

Given:
Radius of a krypton atom = 1.9 A = 1.9 x 10⁻¹⁰ m

Part (a)
$1.9\,A = (1.9\,A)*(10^{-10}\, \frac{m}{A})*( \frac{1}{10^{-8}} \frac{nm}{m}) } =0.019\,nm$
Answer: 0.019 nm

Part (b)
The diameter of a krypton atom = 2*1.9A = 3.8 A = 3.8 x 10⁻¹⁰ m.
The number of krypton atoms within a length of 1.0 mm is
$\frac{1.0\, mm}{3.8 \time 10^{-10}\, m} = \frac{10^{-3}\, m}{3.8 \times 10^{-10} \,m} =2.632 \times 10^{6}$

Answer: About 2.632 x 10⁶ atoms

Part (c)
The radius of a krypton atom is
1.9 A = (1.9 x 10⁻¹⁰ m)*(10² cm/m) = 1.9 x 10⁻⁸ cm
The volume of a krypton atm is
$\frac{4 \pi }{3} (1.9 \times 10^{-8} \, cm)^{3} = 2.873 \times 10^{-23} \, cm^{3}$

Answer: 2.873 x 10⁻²³ cm³

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3 years ago

In simple harmonic motion, the speed is greatest at that point in the cycle when

Charra [1.4K]

The restoring force in a simple harmonic oscillator acts as a restoring force, acting opposite in direction of and proportional in magnitude to the displacement. This has the result that when the oscillator reaches the equilibrium point, it has gained its maximum kinetic energy (and therefore velocity) while the magnitude of the restoring force, and therefore the acceleration, is 0.

Choice A

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4 years ago

Find the deBroglie wavelength of an electron with 4.0 eV.

pantera1 [17]

Explanation:

It is given that,

Voltage, $V=4 eV=4\times 1.6\times 10^{-19}\ V= 6.4\times 10^{-19}\ V$

De broglie wavelength in terms of voltage is given by :

$\lambda=\dfrac{h}{\sqrt{2meV} }$

m and e are the mass and charge on electron. So,

$\lambda=\dfrac{12.27}{\sqrt{V} }\ A$

$\lambda=\dfrac{12.27}{\sqrt{6.4\times 10^{-19}} }\ A$

$\lambda=1.53\times 10^{10}\ A$

$\lambda=1.53\ m$

So, the De broglie wavelength of an electron is 1.53 meters. Hence, this is the required solution.

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3 years ago

Describe the frequency and wavelength range of radio waves

sammy [17]

Answer:

Radio waves are a type of electromagnetic radiation with wavelengths in the electromagnetic spectrum longer than infrared light. They have frequencies from 300 GHz to as low as 3 kHz, and corresponding wavelengths from 1 millimeter to 100 kilometers.

Explanation:

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3 years ago

A jogger accelerates from rest to 3.0 m/s in 2.0 s. A car accelerates from 38.0 to 41.0 m/s also in 2.0 s. (a) Find the accelera

Tom [10]

Answer:

a) The acceleration of the jogger is 1.5 m/s²

b) the acceleration of the car is also 1.5 m/s²

c) Yes, the car travels 76 m farther than the jogger.

Explanation:

a) The acceleration of an object is the variation of its velocity over time:

a = final velocity - initial velocity / time

for the jogger:

a = 3.0 m/s - 0 m/s / 2.0 s = 1.5 m/s ²

b) For the car:

a = 41.0 m/s - 38.0 m/s / 2.0 s = 1.5 m/s²

c) Let´s see the position of the car after 2 seconds.

The equation for the position of an accelerated object moving in a straight line is:

x = x0 + v0* t +1/2 * a * t²

Where:

x = position of the car at time "t"

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

Let´s consider x0 = 0 because the origin of the reference system is located where the car starts accelerating. Then:

x = 38,0 m/s * 2 s + 1/2 * 1.5 m/s ² * (2.0 s)²

x = 79 m

In the same way, we can calculate the position of the jogger:

x = 0 m/s * t + 1/2 * 1.5 m/s ² * (2.0 s)²

x = 3 m

The car travels 79 m - 3 m = 76 m farther than the jogger

4 0

3 years ago

Why is it so important to record all the data in a science experiment​

Why is it so important to record all the data in a science experiment