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SashulF [63]
3 years ago
13

Justine purchased computer software for $5,200. With a down payment of $1000 finance the balance at 12% for 6 years. Find the se

miannual payments.
Mathematics
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

662$

Step-by-step explanation:

Total payment= 5200 + (12%×5200$×6)=8944$

remaining payment= 8944-1000 = 7944$

To get semi annual payment:

6 years×2 = 12 installments

semi annual payment= remaining/no. of installments=7944÷12= 662$

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salantis [7]

Answer:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                                     \displaystyle \lim_{x \to c} x = c

L'Hopital's Rule

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}

When we directly plug in <em>x</em> = 0, we see that we would have an indeterminate form:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

\displaystyle  \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle  \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}

Plugging in <em>x</em> = 0 again, we would get:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}

Substitute in <em>x</em> = 0 once more:

\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0
3 years ago
In her first five basketball games, Tara scored 10, 11, 15, 16, and 18 points. What is the mean absolute deviation for this set
Daniel [21]
Hello there, and thank you for posting your question here on brainly.

To find mean absolute deviation, (MAD) you have to add all the numbers together, and then divide by how much numbers are in the set.

So we have to do 10 + 11 + 15 + 16 + 18, and then divide by 5.

10 + 11 + 15 + 16 + 18 ===> 70

Now, divide by 5.

70 / 5 ===> 14

The mean absolute deviation is 14.

Hope this helped! ☺♥
3 0
4 years ago
Plz help again. I will give 20 points again. NO BAD BOI/GURL
VladimirAG [237]

Answer: So for the first drop-down its 22, and for the 2nd drop-down 2-3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Three examples of front end estimation
BARSIC [14]

Answer: 20, 300, -50, 1,000, 80,000. Take the number 32; the choices to replace it with are 30 or 40 (they both have only one non-zero digit).

Step-by-step explanation: In front-end estimation, we replace the original number with a number that's close by but only has one non-zero digit.

5 0
3 years ago
Read 2 more answers
Please ASAP because i need to submit nowww
Maslowich

Answer:

(-8 , 2)

Step-by-step explanation:

5 0
2 years ago
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