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Vlad [161]
3 years ago
15

A fire hose ejects a stream of water at an angle of 35.0° above the horizontal. The water leaves the nozzle with a speed of 25.

0 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?
Physics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

The fire hose be located 59.80 m away to hit the highest possible fire.

Explanation:

Vertical velocity = 25 sin35 = 14.34 m/s

Acceleration = -9.81m/s²

At maximum height , final vertical velocity = 0 m/s

We have v = u + at

Substituting

           0 = 14.34 - 9.81 x t

           t = 1.46 s

Time of flight of water = 2 x 1.46 = 2.92 s

Horizontal velocity = 25 cos35 = 20.48 m/s

Horizontal displacement = 20.48 x 2.92 = 59.80 m

So, the fire hose be located 59.80 m away to hit the highest possible fire.

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An 85 kg man and his 35 kg daughter are sitting on opposite ends of a 3.00 m see-saw. The see-saw is anchored in the center. If
wolverine [178]

Answer:

0.54m

Explanation:

Step one:

given data

length of seesaw= 3m

mass of man m1= 85kg

weight = mg

W1= 85*10= 850N

mass of daughter m2= 35kg

W2= 35*10= 350N

distance from the center= (1.5-0.2)= 1.3m

Step two:

we know that the sum of clockwise moment equals the anticlockwise moment

let the distance the must sit to balance the system be x

taking moment about the center of the system

350*1.3=850*x

455=850x

divide both sides by  850

x=455/850

x=0.54

Hence the man must sit 0.54m from the right to balance the system

3 0
3 years ago
Atoms are the smallest portions of an element that retain the original characteristics of the element. True or false
kozerog [31]

Answer:

True

Explanation:

Going even smaller than atoms would get you to subatomic particles such as quarks. From there, it is impossible to distinguish elements. So, yes, atoms are the smallest portions of an element that retains the original characteristic of the element.

4 0
3 years ago
The engineer of a passenger train traveling at 25.0m/s sights a freight train whose caboose is 200m ahead on the same track. The
Vika [28.1K]

Answer:

No, there won't be a collision.

Explanation:

We will use the constant acceleration formulas to calculate,

v = u + a*t

0 = 25 + (-0.1)*t

t = 250 seconds (the time taken for the passenger train to stop)

v^2 = u^2 + 2*a*s

0 = (25)^2  + 2*(-0.1)*s

s = 3125 m (distance traveled by passenger train to stop)

If the distance traveled by freight train in 250 seconds is less than (3125-200=2925 m) than the collision will occur

Speed*time = distance

Distance = (15)*(250)

Distance = 3750 m

As the distance is way more, there won’t be a collision

5 0
3 years ago
Shanti is riding on a train that is moving at a speed of 90 km/h. He is carrying a power cord for his phone that is 1.2 m long.
faltersainse [42]

Answer:equal to 1.2 m

Explanation: i took the test

3 0
3 years ago
Read 2 more answers
Barium, a group 2 element, forms an ionic compound with sulfur, a group 16 element. What is the formula for barium sulfide?
WITCHER [35]

Answer:BaS

Explanation:

Ba- barium

S-sulfur

6 0
2 years ago
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