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Vlad [161]
2 years ago
15

A fire hose ejects a stream of water at an angle of 35.0° above the horizontal. The water leaves the nozzle with a speed of 25.

0 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?
Physics
1 answer:
erma4kov [3.2K]2 years ago
5 0

Answer:

The fire hose be located 59.80 m away to hit the highest possible fire.

Explanation:

Vertical velocity = 25 sin35 = 14.34 m/s

Acceleration = -9.81m/s²

At maximum height , final vertical velocity = 0 m/s

We have v = u + at

Substituting

           0 = 14.34 - 9.81 x t

           t = 1.46 s

Time of flight of water = 2 x 1.46 = 2.92 s

Horizontal velocity = 25 cos35 = 20.48 m/s

Horizontal displacement = 20.48 x 2.92 = 59.80 m

So, the fire hose be located 59.80 m away to hit the highest possible fire.

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2. Light waves of the wavelength of 650 nm and 500 nm produce interference fringes on a screen at a distance of 1m from a double
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5 0
3 years ago
A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string
Darya [45]

Answer:

a

The  speed of  wave is   v_1  = 129.1 \ m/s

b

The new speed of the two waves is v =  129.1 \ m/s

Explanation:

From the question we are told that

    The mass of the string is  m  =  60 \ g  =  60 *10^{-3} \ kg

    The length is  l  =  2.0 \ m

    The tension is  T  = 500 \ N

Now the velocity of the first wave is mathematically represented as

     v_1  = \sqrt{ \frac{T}{\mu} }

Where  \mu is the linear density which is mathematically represented as

      \mu  =  \frac{m}{l}

substituting values    

     \mu  =  \frac{ 60 *10^{-3}}{2.0 }

     \mu  =  0.03\ kg/m

So

   v_1  = \sqrt{ \frac{500}{0.03} }

   v_1  = 129.1 \ m/s

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

     

8 0
3 years ago
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