i think photons with shorter wavelengths have larger speed.
I apologise if its incorrect.
Answer:
i think it is <u>teacher</u>
Explanation:
because it is noun
Answer:
Explanation:
Given,
Number of turns, N = 645 N
Area, A = 20.25 m²
Earth Magnetic field, B = 5 x 10⁻⁵ T
Maximum Emf = 1.25 V.
Angular velocity, ω = ?
Using Induced Emf formula
Angular velocity of the coil =
Answer:
Incomplete question
This is the completed question
If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?
Explanation:
Using ohms law as our basis
Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current
V∝I
Resistance is the constant of proportionality
Then
V=iR
Since we want a relationship between current and resistance.
then, I=V/R
So, current is inversely proportional to Resistance
as the current increase the resistance reduce and as the current reduces the resistance increases.
a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.
From ohms law
V=iR
When v =1.5V
I=1.5/R
When V increase to 12V
I=12/R
I.e, it increases by a factor of 8. Eight times it's initial value
b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.
Answer:
magnitude is 1382.59 N/C
Explanation:
Given the data in the question;
The time taken is;
t = x / v
we substitute;
t = ( 2 × 10⁻²) / ( 5.69 × 10⁶ )
t = 3.5149 × 10⁻⁹ s
next, the acceleration is;
a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]
a = 2.42826 × 10¹⁴ m/s²
now, the electric field is;
E = ma / q
we know that;
mass of electron m = 9.11 × 10⁻³¹ kg,
charge of electron q = 1.60 × 10⁻¹⁹ coulomb
we substitute
E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹
E = 2.21214 × 10⁻¹⁶ / 1.60 × 10⁻¹⁹
E = 1.3826 × 10²¹
E = 1382.59 N/C
Therefore, magnitude is 1382.59 N/C
