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Elodia [21]
3 years ago
9

A 13.8 kg block and a 25.5 kg block are resting on a horizontal frictionless surface. between the two is squeezed a spring (spri

ng constant = 1131 n/m). the spring is compressed by 0.164 m from its unstrained length and is not attached permanently to either block. with what speed does each block move away when the mechanism keeping the spring squeezed is released and the spring falls away?
Physics
1 answer:
raketka [301]3 years ago
4 0
Some dogs may inherit a susceptibility to epilepsy.

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the rates of rock formation are similar. i could be wrong tho.....

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1. If the strength of the magnetic field at A is 16 units, the strength of the magnetic field at B is _____.
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1. The strength of magnetic field at A is 64 unit, then the magnetic field strength at B. is 256 units.

64 × 64 = 256 units.

2. If the strength of magnetic field B is 6 units then the strength magnetic field at A is 24 units.

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Our Sun shines bright with a luminosity of 3.828x10^26 Watt. Her energy is responsible for many processes and the habitable temp
Sav [38]

Answer:

(a) 1317.44 W/m²

(b) 1.74×10¹⁵ litres of heating oil

(c) -20.63°C

(d) Energy storage in the Earth and the air

Explanation:

The parameters given are;

Luminosity of the Sun = 3.828 × 10²⁶ Watt

Distance of the Earth from the Sun, d = 152.06 × 10⁶ km

The radius of the Sun = 696 × 10³ km

The radius of the Earth, r_E = 6730 km

The surface area of the Sun = 12000 × Surface area of the Earth

The surface area of the Sun = 6.09 × 10¹² km²

Cross sectional area of the Earth = 1.27 × 10⁴ m² = 0.0127 km²

By the inverse square law, we have;

R = \dfrac{Luminosity \, of \, the \, Sun}{4 \pi d^2}

Where:

R = Solar radiation reaching the Earth

Therefore;

R = \dfrac{3.828 \times 10^{26}}{4 \times \pi \times (1.5206 \times 10^{11})^2} = 1317.44 \ W/m^2

Hence, the energy, E, reaching the Earth in a day is given as follows;

E = R × 4×π×r_E²×60×60×24 = 1317.44 × 4 × π × 6730000² × 60×60×24

E = 6.479×10²² Joules

(b) The number of litres of heating oil is therefore;

6.479×10²² J ÷ (37.3×10⁶ J/litre) = 1.74×10¹⁵ litres of heating oil

(c) 30% of the Energy is reflected, therefore;

0.7 × 6.479×10²² Joules = 4.54×10²² Joules reaches the Earths surface

From Stefan-Boltzmann law, we have;

T = \left (\dfrac{\left (1 - \alpha  \right ) \times R }{4\times \sigma }   \right )^{\dfrac{1}{4}}

Where:

α = 0.3

σ = Stefan-Boltzmann constant = 5.6704×10⁻⁸ W/(m²·K⁴)

Therefore;

T = \left (\dfrac{\left (1 - 0.3 \right ) \times 1317.44 }{4\times 5.6704 \times 10^{-8} }   \right )^{\dfrac{1}{4}} = 252.52 \ K = -20.63 ^{\circ} C

(d) The heat storage in the Earth and the air

7 0
3 years ago
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