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Paul [167]
3 years ago
11

Why a small car can stop easier than an 18 wheeler while traveling at 70 mph down the interstate?

Physics
1 answer:
almond37 [142]3 years ago
3 0
Smaller cars have less momentum than bigger cars. What’s in motion stays in motion but objects with more momentum (can be from weight or from speed but in this case it’s about weight) tend to stay in motion longer.
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What defines minerals will mark brainlest if croccted right
zvonat [6]
<span> Uniform chemical composition
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3 years ago
A system has two possible energy states, E0 and E1 (with E1 &gt; E0). If the difference between these energy states grows (E0 an
Ugo [173]

Answer:

The number of particles in state E0 over the number of particles in state E1  will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart  means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1  will reduce.

5 0
3 years ago
An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring
BlackZzzverrR [31]

Answer:

a) s = 0.603\,m, b) s = 2.412\,m

Explanation:

a) The system ice cube-spring is modelled by means of the Principle of Energy Conservation. Let assume that height at the bottom is zero:

U_{g} = U_{k}

m\cdot g \cdot s\cdot \sin \theta = \frac{1}{2}\cdot k \cdot x^{2}

s = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \sin \theta}

s = \frac{(25\,\frac{N}{m} )\cdot (0.1\,m)^{2}}{2\cdot (0.05\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 25^{\textdegree}}

s = 0.603\,m

b) The distance travelled by the ice cube is:

s = \frac{(25\,\frac{N}{m} )\cdot (0.2\,m)^{2}}{2\cdot (0.05\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 25^{\textdegree}}

s = 2.412\,m

7 0
3 years ago
Read 2 more answers
Auroras are frequently seen
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hope this helps
3 0
3 years ago
The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The
12345 [234]

Answer:

The electric field is 8.75 \times 10^{6}~v~m^{-1} and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field (\vec{E}) is given by \vec{E} = - \nabla V, 'V' being the potential.

In 1-D, it can be written as

E=\dfrac{V}{d}

where 'd' is the separation of space in between the potential difference is created.

Given, V = 0.070~V~ and the thickness of the cell membrane is d = 8.0 \times 10^{-9}~m.

Therefore the created electric field through the cell membrane is

E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}

5 0
3 years ago
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