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2 years ago

Which of the following is a unit of speed?

Physics

2 answers:

exis [7]2 years ago

8 0

Answer:

D, km/s^2

Explanation:

This is a unit of speed because it is saying kilometers over seconds squared, and that is a unit of speed similar to miles per hour or mph or m/h.

dangina [55]2 years ago

7 0

Answer:

Option c that it means cm/year.

Explanation:

Nm means nanometer, 1x10^9m

Km/s^2 is acceleration

h.. it may be height

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A car on a freeway speeds up to get around another car. The car speeds up from 20 m/s to 35 m/s in 5 seconds.

Tanzania [10]

Answer:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

Explanation:

Directly from the information given:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

5 0

2 years ago

A motorcycle has 100,000 J of kinetic energy and is traveling at 20 m/s. Find its mass.

tankabanditka [31]

Answer:

<h3>The answer is 500 kg</h3>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{2KE}{ {v}^{2} } \\$

v is the velocity

KE is the kinetic energy

From the question we have

$m = \frac{2 \times 100000}{ {20}^{2} } = \frac{200000 }{400} = \frac{2000}{4} \\$

We have the final answer as

Hope this helps you

7 0

2 years ago

What is the highest and lowest frequency a human being can hear

nata0808 [166]

Every person is different. But for a planet-wide overall average that roughly represents all human beings on Earth, the figures usually used are:

from 20 Hz to 20,000 Hz .

6 0

2 years ago

Our sun is unusual because it does not belong to a(n) ____

lesantik [10]

The answer is binary star system

5 0

3 years ago

Read 2 more answers

You are given a parallel plate capacitor that has plates of area 27 cm^2 which are separated by 0.0100 mm of nylon (dielectric c

deff fn [24]

Answer:

Applied voltage should be 13.5396 kV

Explanation:

The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by

$Q=\frac{K\epsilon _{o} A}{d}V$

Solving for V we get

$V=\frac{Qd}{K\epsilon _{o}A}$

thus to store a charge of 0.11mC we solve for V as follows

Applying values we get

$V=\frac{0.11\times 10^{-3}\times 0.01\times 10^{-3}}{27\times 10^{-4}\times 3.4\times 8.85\times 10^{-12}}$

$\therefore V=13.5396kV$

7 0

3 years ago