Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
In case of perfectly inelastic collision v'1 and v'2 are same.
We have following information:
m₁=3 kg
m₂=? kg
v₁=x m/s
v₂=0 m/s
v'1 = v'2 = 1/3 * v₁
Now we insert given information and solve for m₂:
3*v₁ + 0*? = 3*1/3*v₁ + m₂*1/3*v₁
3v₁ = v₁ + m₂*1/3*v₁
2v₁ = m₂*1/3*v₁
2 = m₂*1/3
m₂= 6kg
Mass of second mud ball is 6kg.
Answer: the drink cooled down to the same temperature as the room it was in.
Explanation: due to the change and temperature of the room, it cause the heat particles to exchange, causing it cool
Answer:2.67kgm/s cube
Explanation: density = mass ÷ volume = 400 ÷ 150
The first question would be A
The second would be either A or D
The largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.
The given parameters;
- <em>distance between the two black holes, r = 10 AU = 1.5 x 10¹² m</em>
- <em>gravitational force between the two black holes, F = 6.9 x 10²⁵ N.</em>
- <em>combined mass of the two black holes = 5.20 x 10³⁰ kg</em>
The product of the two masses is calculated from Newton's law of universal gravitational as follows;
The sum of the two masses is given as;
m₁ + m₂ = 5.2 x 10³⁰ kg
m₂ = 5.2 x 10³⁰ kg - m₁
The first mass is calculated as follows;
m₁(5.2 x 10³⁰ - m₁) = 2.328 x 10⁶⁰
5.2 x 10³⁰m₁ - m₁² = 2.328 x 10⁶⁰
m₁² - 5.2 x 10³⁰m₁ + 2.328 x 10⁶⁰ = 0
<em>solve the quadratic equation using formula method</em>;
a = 1, b =- 5.2 x 10³⁰, c = 2.328 x 10⁶⁰
The second mass is calculated as follows;
m₂ = 5.2 x 10³⁰ kg - m₁
m₂ = 5.2 x 10³⁰ kg - 4.7 x 10³⁰ kg
m₂ = 5 x 10²⁹ kg
or
m₂ = 5.2 x 10³⁰ kg - 4.9 x 10²⁹ kg
m₂ = 4.7 x 10³⁰ kg
Thus, the largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.
Learn more here:brainly.com/question/9373839
