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diamong [38]
3 years ago
15

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold? adult tickets
Mathematics
2 answers:
USPshnik [31]3 years ago
5 0

Answer:

168 is the answer

Step-by-step explanation:

-Dominant- [34]3 years ago
3 0

Answer:

168

Step-by-step explanation:

The first equation given is 0.50 a +3.75 b= 2071.50

Where a is number of adult tickets and b is number of student tickets

It is also given that 82 students attended, so we can put "82" in place of "b" and then solve the equation for a:

10.50a+3.75b=2071.50\\10.50a+3.75(82)=2071.50\\10.50a+307.5=2071.50\\10.50a=2071.50-307.5\\10.50a=1764\\a=\frac{1764}{10.50}\\a=168

Hence, 168 adults attended

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krok68 [10]

Answer:

a. mean = 1000

standard deviation = 4358.9

b. expected value of average damage bar Y = 1000

probability bar y exceeds 2000 = 0.011

Step-by-step explanation:

we have p1 = 95%, y1 = 0, p2 = 5%, y2 = 20000

Mean = (0.95 * 0) + (0.05 * 20000)

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var(y) = E(y²) - E(Y)²

= we solve for E(y)²

= 0²*0.95 + 20000²*0.05

= 0 + 20000000

then the variance of y = 20000000 - 1000²

=20000000-1000000

= $19000000

standard  deviation is the square root of variance

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2.

a. Expected value of average is also the mean = 1000

b. we are to find probability that barY exceeds 2000

z=\frac{2000-1000}{\sqrt{19000000/100} }

= 1000/435.889

= 2.29

1-p(z≤2.29)

= 1 - 0.989

= 0.011

so the probability that barY exceeds 2000 is 0.011

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bija089 [108]

9514 1404 393

Answer:

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Step-by-step explanation:

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