Moles of calcium metal used = 100/40.1=2.5 Moles of HBr need to react = 5 moles As the molar ratio is 1 is to 2 among them so Moles=molarity x volume 5=2.25 x volume volume=2.22 litres of HBr required for this reaction ANSWER IS 2.22 LITRES
The correct answer would be the second option. It would would need 2 moles of electrons to reduce one mole of bromine gas into two moles of the bromide ions. This is a reduction reaction. It would be written as:
