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Mashutka [201]
3 years ago
8

I PLEASE HELP! How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 gr

ams of calcium metal? Ca (s) + 2HBr (aq) CaBr2 (aq) + H2 (g)
Chemistry
1 answer:
PtichkaEL [24]3 years ago
8 0
Moles of calcium metal used = 100/40.1=2.5
Moles of HBr need to react = 5 moles 
As the molar ratio is 1 is to 2 among them 
so
Moles=molarity x volume
5=2.25 x volume
volume=2.22 litres of HBr required for this reaction
ANSWER IS 2.22 LITRES
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<u>Explanation</u>:

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3 years ago
A graduated cylinder contains 18.0ml of water. what is the new water level after 35.6g of silver metal with a density of 10.5 g/
AlekseyPX

Answer:

The answer to your question is

1.- Volume = 3.4 ml

2.- Volume = 0.61 ml

3.- Mass = 2872.8 pounds

Explanation:

Problem 1

Volume = 18 ml

mass = 35.6 g

density = 10.5 g/ml

Process

1.- Calculate the volume of silver

Formula

density = \frac{mass}{volume}

solve for volume

volume = \frac{mass}{density}

Substitution

volume = \frac{35.6}{10.5}

<u>volume = 3.4 ml</u>

2.- Problem 2

Total volume = ?

Volume = 18 + 3.4

Volume = 21.4 ml

Data

mass = 8.3 g

density = 13.6 g(ml

volume = ?

Formula

density = \frac{mass}{volume}

Solve for volume

volume = \frac{mass}{density}

Substitution

volume = \frac{8.3}{13.6}

Result

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3.- Problem 3

Data

volume = 345 gal

density = 1 g/ml

mass = ?

Formula

density = \frac{mass}{volume}

Solve for mass

mass = density x volume

Covert gal to ml

                            1 gal --------------- 3785 ml

                         345 gal -------------  x

                            x = (345 x 3785) / 1

                            x = 1305825 ml

Substitution

mass = 1 x 1305825

mass = 1305825 g

Convert g to pounds

                        1 g ------------------- 0.0022 pounds

              1305825 g ----------------   x

                        x = (1305825 x 0.0022)

                       <u> x = 2872.8 pounds</u>

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